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3 years ago

What is the base of this exponent?

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

Answer:

Step-by-step explanation:

base is not the exponent but the number being multiplied by the exponent

Lilit [14]3 years ago

6 0

The answer is 4 i believe

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Solve the following:

GrogVix [38]

The answer you are looking for is 2& 3/10

7 0

2 years ago

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The wingspans of Rodrigues fruit bats are normally distributed, with a mean of 82.5 centimeters and a standard deviation of 2.5

IrinaK [193]

81.5%
i honestly looked at the numbers in the problem

6 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Karen batting average was 0.444 She was at bat 45 times.how many hits did she get?

Simora [160]

<span>Karen got an average of 0.444 hits out of 45 bats.
We need to find the number of hits did Karen got.
=> 45 bats all in all
=> 0.444 average hits
x = how many hit did she get
Now, let’s multiply the total bats to Karen’s average hit:
=> 45 x 0.444 …. (repeating decimals)
=> 20
Therefore, Karen hit 20 times out of 45 bats
Let’s check our answer:
=> 20 / 45
=> 0.44444…. (repeating decimals)

</span>

4 0

3 years ago

Read 2 more answers

17.83 rounded to the nearest tenth

garri49 [273]

The answer would be 17.8 hope this help you

4 0

3 years ago