Answer:
Step-by-step explanation:
so we know a few things about t his triangle, it's a special one :P , it's called isosceles because two of the legs are the same length, which also mean that the angle x is the same at the other unknown angle sooo there are 2 x's if that makes sense? and then we can solve this , b/c we also know that the interior angles of a triangle add up to 180°
180 = 32 + 2x
148 = 2x
74 =x
∠x = 74°
If K is midpoint of JL then JK = 0.5JL
JL = 4x - 2; JK = 7
The equation:
0.5(4x - 2) = 7
2x - 1 = 7 |add 1 to both sides
2x = 8 |divide both sides by 2
<u>x = 4</u>
<u>JL</u> = 4(4) - 2 = 16 - 2 = <u>14</u>
<u>KL</u> = JK =<u> 7</u>
The answer is 1.2 hope this helped ;)
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
