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zvonat [6]
3 years ago
12

Please help me with this question. Geometry

Mathematics
1 answer:
natta225 [31]3 years ago
4 0
DC is parallel to AB

You can see this because DB is the traversal by looking at where the angles are formed
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Quadrilateral CDEF is reflected across the x-axis and translated 3 units left to create quadrilateral GHJK. http://prntscr.com/i
eimsori [14]
To answer this question, you will reflect the original shape to make a new trapezoid at K(2, -1), G (2, -4), H(6, -4), and J (6, -2).  You will keep the y value in each ordered pair and write the opposite x value to show the reflection.

These are all then translated 3 units left to create the new ordered pairs:

K(-1, -1), G(-1, -4), H(3, -4), J(3, -2)

The two parallel sides are KG and JH.  These were originally CF and DE.
7 0
3 years ago
What is the value of f(16) - f(0) when f(x) = 4x - 8?
levacccp [35]
That would be 4(16) - 8 - (4(0) - 8) = 64 - 9 - 0 + 8 = 63 Answer
5 0
3 years ago
Read 2 more answers
The winner of a raffle will receive 3/4 of the $530.40 raised from raffle ticket sales. How much money will the winner get? (Ple
slamgirl [31]
$530.40/4= $132.60
$132.60 x 3=$397.80

Or
$530.40 x .75= $397.80
7 0
3 years ago
suppose a population of 250 crickets doubles in size every six months. How many crickets will there be after two years?
lord [1]

double every 6 months 

in 6 months there would be 250*2 = 500 crickets

 in 1 year there would be 500*2 = 1000 crickets

in 1.5 years there would be 1000 *2 = 2000 crickets

 in 2 years there would be 2000 *2 = 4000 crickets

4 0
3 years ago
The probability that a single radar station will detect an enemy plane is 0.65. (a) How many such stations are required to be 98
Inga [223]

Answer:

4 stations

Step-by-step explanation:

If we need to be at least 98% certain that an enemy plane flying over will be detected by at least one station, we must ensure that there is at most a 2% chance that no radar stations detect the plane.

The probability that a single radar station does not detect the plane is 0.35.

For n radar stations:

P=0.02=0.35^n\\n=\frac{log(0.02)}{log(0.35)}\\n=3.73

Rounding up to the next whole station, at least 4 stations are needed.

4 0
3 years ago
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