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Two identical objects are moving directly toward one another at the same speed v. ~v −~v m m What is the total kinetic energy of

Natalka [10]

<span>Answer: Correct answer is just add the two kinetic energies; E = (1/2)mv^2 + (1/2)mv^2</span>

5 0

3 years ago

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A 4.25 kg block is sent up a ramp inclined at an angle theta=37.5° from the horizontal. It is given an initial velocity ????0=15

wel

Answer:

d = 11.79 m

Explanation:

Known data

m=4.25 kg : mass of the block

θ =37.5° :angle θ of the ramp with respect to the horizontal direction

μk= 0.460 : coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.

Forces acting on the block

W: Weight of the block : In vertical direction

N : Normal force : perpendicular to the ramp

f : Friction force: parallel to the ramp

Calculated of the W

W= m*g

W= 4.25 kg* 9.8 m/s² = 41.65 N

x-y weight components

Wx= Wsin θ= 41.65*sin 37.5° = 25.35 N

Wy= Wcos θ =41.65*cos 37.5° =33.04 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay ay = 0

N - Wy = 0

N = Wy

N = 33.04 N

Calculated of the f

f = μk* N= 0.460*33.04

f = 15.2 N

We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax , ax= a : acceleration of the block

-Wx-f = m*a

-25.35-15.2 = (4.25)*a

-40.55 = (4.25)*a

a = (-40.55)/ (4.25)

a = -9.54 m/s²

Kinematics of the block

Because the block moves with uniformly accelerated movement we apply the following formula to calculate the final speed of the block :

vf²=v₀²+2*a*d Formula (2)

Where:

d:displacement (m)

v₀: initial speed (m/s)

vf: final speed (m/s)

Data:

v₀ = 15 m/s

vf = 0

a = -9.54 m/s²

We replace data in the formula (2) to calculate the distance along the ramp the block reaches before stopping (d)

vf²=v₀²+2*a*d

0 = (15)²+2*(-9.54)*d

2*(9.54)*d = (15)²

(19.08)*d = 225

d = 225 / (19.08)

d = 11.79 m

3 0

3 years ago

.A coin rolls off the edge of a table. The coin

geniusboy [140]

Answer:

Apply the following formulae horizontally And get A value for time

Remember horizontal acceleration is zero

$s = ut + \frac{1}{2}a {t}^{2} \\ 0.8 = 1.7 \times t \\ \frac{0.8}{1.7} = t \\ t = 0.47s$

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

$s = ut + \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} \times 10 \times (0.47) ^{2} \\ s = 1.1045m$

5 0

3 years ago

As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p

kherson [118]

Explanation:

The Coulomb's law states that the magnitude of each of the electric forces between two point-at-rest charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

$F=\frac{kq_1q_2}{d^2}$