3 years ago

I’ll love you forever if you help me <3

Physics

1 answer:

lana66690 [7]3 years ago

7 0

It’s meee ;) answer is 1.7 (d)

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Calculate the potential difference across a 10 ohm register carrying a current of 2.5 ampere

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Find the change in velocity of a 369 g hockey puck subject to the force shown below.

Elena-2011 [213]

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The change in velocity is 15.83 [m/s]

Explanation:

Using the Newton's second law we have:

ΣF = m*a

The force in the graph is 185 N, therefore:

$185=0.369*a\\Where\\a=acceleration made it by the force [m/s^2]$

$a=501.35[m/s^2]$

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$V^{2}=Vi^{2} + 2*a*(x-xi) \\where\\V=final velocity [m/s]\\Vi= initial velocity [m/s] = 0 the hockey disk is in rest when receives the hit.\\ x = Final position [m] = 0.4 m\\xi = initial position [m] = 0.15m\\$

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$V^{2}=0 + 2*501.35*(0.4-0.15)\\ \\V= 15.83[m/s]$

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