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ELEN [110]
4 years ago
11

Science cannot be used to answer questions about _____.

Physics
2 answers:
aksik [14]4 years ago
8 0
Science cannot be used to answer questions about Moral judgements
nexus9112 [7]4 years ago
8 0
Moral judgements. !!!!!!!!!
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If a biker rides west for 50 miles from his starting position, then turns and bikes back east for 80 miles. What is his displace
lara [203]

Answer:

Displacement = 30 miles due east.

Explanation:

Let the distance due west be A

Let the distance due east be B

Given the following data;

A = 50 miles

B = 80 miles

To find the displacement;

Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.

Thus, the displacement would be calculated by subtracting distance A from distance B because the rider rode in opposite directions.

Displacement = B - A

Displacement = 80 - 50

Displacement = 30 miles due east.

7 0
3 years ago
Locate the element helium (He) on the periodic table. What is the period number in which helium is found? What is the group name
Digiron [165]

period 1 and group 18 or 8A

8 0
4 years ago
Read 2 more answers
A Canadian driving from Quebec to Montreal finds he has traveled 271 km. How many miles is this? There are 1.61 km in 1 mi
kotegsom [21]

Answer:

168.32 mile

Explanation:

1 mile = 1.61 km

1.61 km = 1 mile

1 km = 1 / 1.61 mile

So, 271 km = 271 / 1.61 = 168.32 mile

3 0
3 years ago
A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on
Anarel [89]

Answer:

b

Explanation:

7 0
3 years ago
A 20~\mu F20 μF capacitor has previously charged up to contain a total charge of Q = 100~\mu CQ=100 μC on it. The capacitor is t
sertanlavr [38]

Explanation:

The given data is as follows.

       C = 20 \times 10^{-6} F

        R = 100 \times 10^{3} ohm

        Q_{o} = 100 \times 10^{-6} C

          Q = 13.5 \times 10^{-6} C

Formula to calculate the time is as follows.

          Q_{t}  = Q_{o} [e^{\frac{-t}{\tau}]

       13.5 \times 10^{-6} = 100 \times 10^{-6} [e^{\frac{-t}{2}}]

               0.135 = e^{\frac{-t}{2}}

         e^{\frac{t}{2}} = \frac{1}{0.135}

                         = 7.407

           \frac{t}{2} = ln (7.407)

                      t = 4.00 s

Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.

4 0
3 years ago
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