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Naddik [55]
2 years ago
15

What is the smallest integer for which the inequality 120-8x<-16

Mathematics
1 answer:
Iteru [2.4K]2 years ago
8 0

Answer:

x > 17

Step-by-step explanation:

120 -8x <  -16\\- 120\\\frac{-8x}{-8}  < \frac{-136}{-8}\\x > 17

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Solve |2x - 2| &lt; 8
Alex777 [14]

Answer:

C

Step-by-step explanation:

|2x - 2| < 8

it implies that

2x - 2 < 8

2x -2 + 2 < 8 + 2

2x < 10

x < 5

or

-(2x - 2) < 8

-2x + 2 < 8

-2x + 2 - 2 < 8 - 2

- 2x < 6

x > -3 ( the sense of the inequality reverse because I divided by minus)

The solution can be combine to

-3<x<5

4 0
3 years ago
Which interval describes where the graph of the function is positive?
Ad libitum [116K]

Answer:

D is the correct answer.

Step-by-step explanation:

Find the portion of the graph that is above the x-axis.

8 0
1 year ago
Read 2 more answers
A figure is composed of a rectangle and a right triangle. What is the area of the figure?
strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h

We substitute the values to obtain;

Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm

Area=\frac{1}{2}(21.6cm)\times 6cm

Area=64.8cm^2

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

C=2\pi r

where r=3.5ft is the radius of the circular table cloth.

We substitute this value and \pi=3.14 into the formula to get;

C=2(3.14)(3.5)ft

C=21.98ft

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

C=\pi r

where r=12.5cm is the radius of the semicircle.

C=3.14\times 12.5cm

C=39.25cm

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh

Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24

Area=345.3125+300

Area=645.3125cm^2

Area\approx645cm^2

QUESTION 6

The area of the parallelogram is given by the formula;

A=bh

From the diagram, b=y\:in.,h=3in..

Given, A=23.7 inches squared.

We substitute the values to obtain;

23.7=3y

y=\frac{23.7}{3}

y=7.9in.

QUESTION 7

The area of a rectangle is given by the formula;

Area=l\times b

The area of the bigger rectangle =9\times15=135in^2

The area of the smaller rectangle =8\times 13=104in^2

The area of the  shaded region =135-104=31in^2

5 0
3 years ago
Please Help (10 Points) I Really Need Help! Please Show Ur Work!
elena55 [62]
To find the mean add up all the numbers given then divide your answer by how many numbers there are.
for ex: 1,2,3,4,5
1+2+3+4+5= 15
15 divided by 5 = 3
so the mean is 3

5 0
2 years ago
What is 18 hours into minutes. Thanks!
avanturin [10]
Shrrrr 18 into 1 min bruh
3 0
3 years ago
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