Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
This is not correct
Step-by-step explanation: I am just a 6th grader but i know this question, it is not correct because potential energy is mostly staying in one place this would be kenetic energy because it is moving.
Based on sss because of congruent
3/4 = 3/4*1
3/4 = 3/4 * 3/3 = 9/12
Box is 9/12 full after heba ate 1/12 of a box of cereal
Initial fraction will be 9/12+1/12
=10/12= 5/6
