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TiliK225 [7]
3 years ago
13

From a list of ten books, how many groups of 4 books can be selected

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

First you have all ten books, but then every time after, you loose one because you can't put the same book in the group twice.

10 * 9 * 8 * 7 = 5040 groups

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The sum of two numbers is 125. Their difference is 47. The two numbers are:
enyata [817]

Answer:

39 and 86.

Step-by-step explanation:

39 and 86 equal 125 when added. When 47 is subtracted from 86 you get 39.

7 0
3 years ago
Factor the expression using the GCF.<br> The expression 18a-12 factored is
Dafna1 [17]

Answer: 6(3a-2)

Step-by-step explanation:

The greatest common factor (GCF) of 18a and -12 is 6. Therefore,

18a-12=6()=6(3a-2)

3 0
2 years ago
Read 2 more answers
Last week, Leon bought 8 pizzas and 13 cakes
romanna [79]
P = pizza and c =cakes

Last week: 8p + 13c = 134
Today: 28p + 4c = 220

Let’s take the formula for today and subtract 28p from each side to isolate the 4c.

4c = 220 - 28p

Now divide each side by 4

c = (220 - 28p)/4
Simplify to c = 55 - 7p

Now go to the formula for last week, substitute the c for 55-7p

8p + 13(55 - 7p) = 134
8p + 715 - 91p = 134

Simplify to 715 - 83p = 134

Let’s add 83p to each side.

715 = 134 + 83p

Subtract 134 from each side

581 = 83p

Divide each side by 83

p = $7
5 0
2 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
Ace_santiago
kupik [55]
The right answer for the question that is being asked and shown above is that: "C. TUVW was rotated 90° counterclockwise about the origin and then translated 4 units to the right." This is the <span>sequence of transformations was performed on figure TUVW to produce figure TꞌꞌUꞌꞌVꞌꞌWꞌꞌ</span>
6 0
3 years ago
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