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4 years ago

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ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ant legs L Elena w

rites a=6 X L and Andre write L=0.166666666667 X a.do you agree with either of the Equations?explain your reasoning

2 answers:

barxatty [35]4 years ago

7 0

Answer:

Neither are correct.

Step-by-step explanation:

The number of legs = the number of ants * 6.

The relationship is L = 6 a so neither are correct.

ludmilkaskok [199]4 years ago

7 0

Answer: Both equations are incorrect.

Step-by-step explanation:

Ants have 6 legs:

The equation of Elena is:

a = 6*L

where a is ants and L is legs.

this equation says that are equal number of ants tan 6 times the number of legs, this is is not the case;

the number of legs is six times the number of ants, because each ant has 6 legs: L =6*a

the Andre equation is:

L = 0.166*a

Which, again, it is incorrect.

in this case the equation should be:

a = 0.166*L

and the ratio of ants to legs is 1:6 wich means that there is one ant for each 6 legs.

Both options are incorrect

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alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS

serious [3.7K]

Answer:

$k=\frac{-11}{2}$ .

Step-by-step explanation:

We are given $\alpha$ and $\beta$ are zeros of the polynomial $x^2-(k+6)x+2(2k-1)$ .

We want to find the value of $k$ if $\alpha+\beta=\frac{1}{2}$ .

Lets use veita's formula.

By that formula we have the following equations:

$\alpha+\beta=\frac{-(-(k+6))}{1}$ (-b/a where the quadratic is ax^2+bx+c)

$\alpha \cdot \beta=\frac{2(2k-1)}{1}$ (c/a)

Let's simplify those equations:

$\alpha+\beta=k+6$

$\alpha \cdot \beta=4k-2$

If $\alpha+\beta=k+6$ and $\alpha+\beta=\frac{1}{2}$ , then $k+6=\frac{1}{2}$ .

Let's solve this for k:

Subtract 6 on both sides:

$k=\frac{1}{2}-6$

Find a common denominator:

$k=\frac{1}{2}-\frac{12}{2}$

Simplify:

$k=\frac{-11}{2}$ .

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3 years ago

Given: S is the midpoint of QR, QR¯⊥PS¯ and ∠RSP and ∠QSP are right angles.<br><br> Prove: PR≅PQ

tigry1 [53]

ΔRSP ≅ ΔQSP by SAS. Therefore, PR ≅ PQ by CPCTC theorem.

<h3>What is the CPCTC Theorem?</h3>

If two triangles are congruent, the CPCTC theorem states that all corresponding parts of the two triangles would also be congruent to each other.

Since S is the midpoint of QR, therefore, RS ≅ QS (one pair of congruent sides)

∠RSP ≅ ∠QSP [right angles] (one pair of congruent included angles)

SP ≅ SP based on the reflexive property (one pair of congruent sides)

Therefore, ΔRSP ≅ ΔQSP by SAS.

Conclusively, PR ≅ PQ by CPCTC theorem.

Learn more about the CPCTC theorem on:

brainly.com/question/6076251

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2 years ago

Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –y equals negative StartFraction one-third EndFr

DiKsa [7]

Answer:

$y=-\frac{1}{3} x+5$

Step-by-step explanation:

Notice that the answers they give you to choose from are all lines in slope y-intercept form, it would be very simple to just find the answer finding yourself the slope and y-intercept of the line in question.

Since they give you two points $(x_1,y_1)$ and $(x_2,y_2)$ for the line, use them to find the slope of the line that goes through them, with the formula: $slope=\frac{y_2-y_1}{x_2-x_1} =\frac{7-6}{-6-(-3)} =\frac{1}{-3} =-\frac{1}{3}$

Therefore, the slope of the line must be $-\frac{1}{3}$

Now, find the y-intercept (b) using the general form of a line with the given slope:

$y=-\frac{1}{3}x +b$

Use one of the given coordinate points to request that the line passes through it. For example, through the point (-3,6) (when x = -3, y must be 6):

$y=-\frac{1}{3} x+b\\6=-\frac{1}{3}(-3)+b\\6=1+b\\b=6-1=5$

then the y-intercept must be 5. Therefore our line is : $y=-\frac{1}{3}x +5$ which appears listed as your second choice.

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3 years ago

Read 2 more answers

A cleaning services charges $1000 for cleaning 20 offices. Cost of cleaning one office is _

vovikov84 [41]

The answer is 50 you would take the 1000 and divide it by 20 to figure out the answer to one which is 50

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2 years ago

Read 2 more answers

A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the

forsale [732]

<h3>The probability of student passing the quiz with at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly = $(\frac{1}{2})$ = p = 0.5

Also, the possibility of answering a question wrong = $(\frac{1}{2})$ = q = 0.5

Now, to pass he needs to answer 8 or more ( 8 , 9 or 10) answers correctly.

P(answering 8 correct answer) = $^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2 = 0.0439$

P(answering 9 correct answer) = $^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1 = 0.0097$

P(answering 10 correct answer) = $^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0 = 0.00097$

So, the total Probability = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz with at least 8 of the questions correct is 0.05457.

6 0

4 years ago