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tankabanditka [31]
2 years ago
12

PLEASE HELP IM SO CLOSE TO BEING DONE I JUST NEED THESE ANSWERS

Mathematics
1 answer:
Artist 52 [7]2 years ago
4 0

Answer: 12

Step-by-step explanation:

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Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai
Nina [5.8K]

Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

Given : Confidence level : (1-\alpha)=0.90

⇒ significance level =\alpha= 0.10

z-value for 90% confidence interval (using z-table)=z_{\alpha/2}=1.645

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

Now, the required sample size will be :

n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2

Simplify , we get

n=(0.25)(6765.0625)=1691.265625\approx1692

Hence, the required sample size = 1692

8 0
3 years ago
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What is 6 plus 3 divided by two?
Aleks [24]

Answer: 7.5

Step-by-step explanation:

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3 years ago
What was hitler and german army trying to accomplish? complete sentences for a summary
Shalnov [3]
Hitler and the Nazis were trying to get as much power as possible they were trying to fix the wrong doings (in there opinion) of the previous German leaders the kaisers so this is why over the course of the moment from when Hitler was elected in 1933 he started to build up the army .
MAIN POINT: He aimed to persecute those of gypsy , Jewish and African or black origin and those with disabilities as he wanted to create his aryan race of pure Germans no this isn’t a summary but take the points out of this
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3 years ago
HELP ME PLEASE: I WILL GIVE BRAINLIEST AND IT IS 20 POINTS
Anastaziya [24]

Answer:

0

Step-by-step explanation:

any log with a base of one and it becomes logv5 (1) after logv5(logV3 (3) because log3(3) equal one so then logv5 (1) is 0

8 0
2 years ago
Find the area of the region that lies inside the first curve and outside the second curve.
marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = \dfrac{1}{2}

\theta = -\dfrac{\pi}{3}, \ \  \dfrac{\pi}{3}

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \  \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \  5^2 d \theta

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \  \theta  d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \   d \theta

A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  \dfrac{cos \ 2 \theta +1}{2}  \end {pmatrix} \ \ d \theta - \dfrac{25}{2}  \begin {bmatrix} \theta   \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}

A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  {cos \ 2 \theta +1}  \end {pmatrix} \ \    d \theta - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}}    \ \ - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{2 \pi}{3} \end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3})  \end {bmatrix} - \dfrac{25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} +   \dfrac{\pi}{3}  \end {bmatrix}- \dfrac{ 25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3}   \end {bmatrix}- \dfrac{ 25 \pi}{3}

A =    \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx
7 0
3 years ago
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