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MrMuchimi
3 years ago
12

Jordan was driving down a road and after 4 hours he had traveled 82 miles. At this speed, how many miles could Jordan travel in

14 hours?
Mathematics
2 answers:
babymother [125]3 years ago
8 0
You can use a proportion.

4 hours is to 82 miles as 14 hours is to x miles

4/82 = 14/x

Cross multiply to get

4x = 14 * 82

4x = 1148

x = 287

287 miles
kari74 [83]3 years ago
8 0
287 miles. 82 divided by 4 is 20.5 multiply that by 14 and that equals 287. I hope it’s right!
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Penelope was reading a book at a rate
valentinak56 [21]

Answer:

Penelope can read 6 pages in 5 minutes.

Step-by-step explanation:

You would use the equation 1.2x = P

P=how many pages    x=how many minutes

1.2(5) = 6

She can read 6 pages in 5 minutes

8 0
3 years ago
What is the slope of the line that passes through the points (-10, -8) and
bazaltina [42]
First of all we have to find the slope


m = y₂-y₁ / x₂-x₁

m = -8 + 16 / -10 + 8

m = 8/-2

m = -4

y-y₁ = m (x-x₁)

y + 8 = -4 (x + 10)

y + 8 = -4x - 40

y = -4x -40 - 8

y = -4x -48
7 0
3 years ago
Which statement describes the relationship between labor cost and time for a car repair?
Nimfa-mama [501]

Answer:

Option A is correct.

Step-by-step explanation:

As we see the graph, we can say that the correct statement is :

A.)All repairs requiring 1 hour or less have the same labor cost. We can see that the coat from 0 hours to 1 hour is $50. So, the number of hours falling in this range has the same repairing cost.

B.) Labor costs the same no matter how many hours are used for a repair. This is wrong as the graph is increasing after 1 hour.

C.) Labor costs for a repair are more expensive as the number of hours increases. This is wrong as the hours are increasing from 0.25 to 0.5 then to 0.75 but they all have the same cost.

D.)There is no cost of labor for a repair requiring less than 1 hour. This is also wrong. The cost is $50.

7 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
Find the slope of the line that passes through the points (0,-11) and (8,-8).
Korolek [52]

To find the slope of a line, we can use the following formula:

\displaystyle \large{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:

\displaystyle \large{(x_1,y_1) = (0, - 11)} \\  \displaystyle \large{(x_2,y_2) = (8, - 8)}

Substitute the points in formula:

\displaystyle \large{m =  \frac{ - 8 -( - 11)}{ 8 - 0} }

Negative multiply negative always come out as positive.

\displaystyle \large{m =  \frac{ - 8  +  11}{ 8 - 0} } \\  \displaystyle \large{m =  \frac{ 3}{ 8 } } \\

Since m stands for slope, we can say that:

\displaystyle  \large \boxed{ \tt{slope  =  \frac{3}{8} }}

5 0
3 years ago
Read 2 more answers
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