Question

A cone has a diameter of 18 in. and a height of 14 in.

Answer 1

Cone's volume is $V = \frac{1}{3}Sh$
where    S - surface area,  h - height
Surface area =  $\pi r^2$

r = 18/2=9
h= 14
π = 3.14
$V= \frac{1}{3} \pi r^2h= \frac{1}{3} *3.14*9^2*14= \frac{1}{3} *3.14*81*14=27*14*3.14$[/tex]
$V = 1186.92$ $in.^3$