Answer:
3pf² - 21p²f + 6pf - 42p²
= 3pf² + 6pf - 21p²f - 42p²
= 3pf(f +2) - 21p²(f + 2)
= (3pf - 21p²)(f +0 2)
Answer: (3pf - 21p²)(f + 2)
Step-by-step explanation:
Answer:
9(p + q)(9p + 9q - 1)
Step-by-step explanation:
Given
81(p + q)² - 9p - 9q ← factor out - 9 from these 2 terms
= 81(p + q)² - 9(p + q) ← factor out 9(p + q) from each term
= 9(p + q)(9(p + q) - 1)
= 9(p + q)(9p + 9q - 1)
Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is

we have

substitute

Solve for x
subtract 30 both sides


Divide by 11 both sides

The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10

Answer:
They are equal when muliplyed by 100
Step-by-step explanation:
-20=-4x-6x
First combine like terms.
-20=-10x
Divide by -10 on both sides
X=2