Ask question

Ask question

All categories

3 years ago

13

The perimeters of two similar polygons are 20 and 28. One side of the smaller polygon is 4. Find the corresponding side of the l

arger polygon.
1) 7
2) 5 3/5
3) 2 6/7
4) 5

2 answers:

Yuliya22 [10]3 years ago

8 0

Answer:

number 2

Step-by-step explanation:

KIM [24]3 years ago

8 0

4 3\5 is the correct answer:)

You might be interested in

In the figure, the radius of the partial circle with center Ais 4 feet.

oee [108]

1)24.50 ;))))))))))

2)45.68 ;)))))))))

7 0

3 years ago

Ok, I was put in a class higher than my level, plz explain how to get the angle too, thx!

dlinn [17]

Answer:

d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

My favorite recipe for lemonade calls for 4 cups of water to 3/4 cups sugar. How

Nikolay [14]

Answer and Step-by-step explanation:

To find the unit rate, divide the 4 cups of water and the $\frac{3}{4}$ cups sugar by 4 to get a unite rate for 1 cut of water.

<u>4 divided by 4 equals 1.</u>

<u />

<u /> $\frac{3}{4}$ <u> divided by 4 equals </u> $\frac{3}{16}$ <u>.</u>

<u />

<u>Now, we multiply </u> $\frac{3}{16}$ <u> by 6.</u>

<u></u> $\frac{9}{8}$ <u> is how many cups of sugar that needs to be measured for 6 cups of water.</u>

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

8 0

3 years ago

The third-degree Taylor polynomial about x = 0 of In(1 - x) is

gizmo_the_mogwai [7]

Answer:

$\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Functions
Function Notation

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

MacLaurin/Taylor Polynomials

Approximating Transcendental and Elementary functions
MacLaurin Polynomial: $\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n$
Taylor Polynomial: $\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n$

Step-by-step explanation:

*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.

<u />

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = ln(1 - x)

Center: x = 0

<em>n</em> = 3

<u>Step 2: Differentiate</u>

[Function] 1st Derivative: $\displaystyle f'(x) = \frac{1}{x - 1}$
[Function] 2nd Derivative: $\displaystyle f''(x) = \frac{-1}{(x - 1)^2}$
[Function] 3rd Derivative: $\displaystyle f'''(x) = \frac{2}{(x - 1)^3}$

<u>Step 3: Evaluate Functions</u>

Substitute in center <em>x</em> [Function]: $\displaystyle f(0) = ln(1 - 0)$
Simplify: $\displaystyle f(0) = 0$
Substitute in center <em>x</em> [1st Derivative]: $\displaystyle f'(0) = \frac{1}{0 - 1}$
Simplify: $\displaystyle f'(0) = -1$
Substitute in center <em>x</em> [2nd Derivative]: $\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}$
Simplify: $\displaystyle f''(0) = -1$
Substitute in center <em>x</em> [3rd Derivative]: $\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}$
Simplify: $\displaystyle f'''(0) = -2$

<u>Step 4: Write Taylor Polynomial</u>

Substitute in derivative function values [MacLaurin Polynomial]: $\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3$
Simplify: $\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

Topic: AP Calculus BC (Calculus I/II)

Unit: Taylor Polynomials and Approximations

Book: College Calculus 10e

5 0

3 years ago

refer back to the first problem on Tuesday,A scale of a map is 1 in:125ft,jon lives 250 feet away from max.how many inches separ

pishuonlain [190]

Answer:

2 inches

Step-by-step explanation:

The scale means 1 inches on map equal 125 feet in real life

<em>We know in real life Jon lives 250 ft away from Max. 250 is twice of 125, hence in map</em>, it should be 1*2=2 inches.

On the map, it is 2 inches from Jon's home to Max's home.

4 0

3 years ago