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2 years ago

PLEASE HELP ASAP !!! 75 points !!! SEE PICS BELOW !!!

Mathematics

2 answers:

lawyer [7]2 years ago

4 0

Answer:

y = 2x + 131

Step-by-step explanation:

kvasek [131]2 years ago

3 0

Answer:

y=2x+105

Step-by-step explanation:

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Write 7^3 × √ 7 as a single power of 7

olga_2 [115]

Step-by-step explanation:

7^3 × 7^(1÷2)

= 7^(3+ 0.5)

=7^3.5 ans

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2 years ago

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padilas [110]

Answer:

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Step-by-step explanation:

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2 years ago

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Find the common ratio of the geometric sequence 18,-72,288,...

tamaranim1 [39]

Answer:

<em>The common ratio of the geometric sequence is -4</em>

Step-by-step explanation:

<u>Geometric Sequence</u>

A geometric sequence is defined as a series of numbers that follow a fixed pattern: Each term equals the previous term times a fixed number called the common ratio. The recursive formula is:

$a_n=a_{n-1}*r$

Where r is the common ratio.

We are given three terms of a geometric sequence:

18,-72,288,...

To find the common ratio, just divide each term by the previous term:

$\displaystyle r=\frac{-72}{18}=-4$

Make sure it's a fixed number and test with the third term:

$\displaystyle r=\frac{288}{-72}=-4$

Since both numbers coincide, the common ratio of the geometric sequence is -4

5 0

2 years ago

Pls help! On the day of the big game, 298 marching band members were waiting to get on the

elixir [45]

Answer:

here u go!

Step-by-step explanation:

each bus can fit 45 people and there are 298 TOTAL. there will be an extra bus with less than 45 people btw.

first divide 298 by 45, you will get 6.2 something. however, you CANNOT have .2 of a bus. the 6 represents 6 buses of 45 people.

now taking that 6 again, multiply it by 45. 45 x 6 = 270. we have 28 people left over, this adds an extra bus.

7 buses will be needed to get them to the game.

4 0

2 years ago

Write the equation of a line that has a slope of 3 and goes through points (2,1)

Inga [223]

Answer:

The equation of straight line is 3 x-y-5=0

Step-by-step explanation:

The equation of straight line having slope m = 3 and passing through the point (2,1) is

the standard form of straight line is $y-y_{1} = m (x-x_{1} )$

now substitute m = 3 and point (2,1) is

$y- 1 = 3(x-2)$

$y - 1 = 3 x - 6$

$3 x-y -6+1=0$

$3 x-y -5 =0$

The equation of straight line is 3 x-y-5=0

3 0

2 years ago