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3 years ago

. Find the values of the variables in ▱DEFG.

Mathematics

1 answer:

DiKsa [7]3 years ago

5 0

Answer:

sorry i dont have enough information

Step-by-step explanation:

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Find the surface area of a cylinder with a height of 4 yd and a base radius of 3 yd.

ad-work [718]

Answer:

131.95yd squared

Step-by-step explanation:

A=2πrh+ 2 r(2)=2*π*3*4+2*π*3(2)~131.94689yd(2)

5 0

3 years ago

Identify the radius and the center of a circle whose equation is (x – 5)² + y² = 81.

forsale [732]

Answer:

centre (5,0)

radius:9

I hope it will be helpfulness

8 0

2 years ago

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

3 years ago

Luke wants to reduce the area of his rectangular garden by one-fourth. The expression 1/4 lw can be used to represent this chang

Leya [2.2K]

Answer:

lw/4

Step-by-step explanation:

Area of a rectangle = length × width

= l × w

Area of a rectangle = let

reduce the area of his rectangular garden by one-fourth

= 1/4 * lw

= 1/4lw

What is another way to write this expression?

Another way to write the expression is

= 1/4 * lw

= lw / 4

3 0

3 years ago

What is the SAME about a line and a segment?

tatiyna

Answer:

they are both straight

Step-by-step explanation:

8 0

3 years ago