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2 years ago

Fill in the table to convert the units of time from hours to minutes or minutes to hours.

1 answer:

4 0

Ok so first we need to under stand that 60 minutes is equivalent to 1 hour, by knowing this we should be able to answer the following. Our first box which needs to be filled in asking how many hours are in 300 minutes, well let’s figure this out. So we know that in 60 minutes it will be equivalent to one hours, so in order to find how many minutes are in 300 minutes we would divide 300 by 60 which give a us 5. Therefore causing the second box to me 5 hours. Our next and final box is asking how many hours are in four minutes well this one is a little harder than our previous one but I’ll help you through it. By following the same procedure as we did the previous question we are going to divide 4 by 60 and we know that dividing like so we are going to get a decimal but that’s ok it’s going to give us the answer we need to fill in the box. By dividing like so we should get a long decimal that look that this 0.066666666666667. I am going to simply this down to 0.0667. Causing my last box to be 0.667.
Summary:
second box: 5 hours
Third box: 0.0667 hours
Hope this helps!!!
Please tell me if I have made an error, I enjoy learning from my mistakes:)
Have a great rest of your day❤️

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How many times greater is 9*10^10 than 3*10^8

vladimir2022 [97]

Answer:

9*10^10/ 3*10^8 = 300

Step-by-step explanation:

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2 years ago

HELLLLLLLLLLLLLLLLPPPPPPP PLEASE! Is the number 4.78 a solution of x < 5? Is the number 6 a solution of x < 6? PLEASE EXPL

Karolina [17]

As you know, 4.78 is less than 5, so
.. yes, x=4.78 is a solution to x < 5

As you know, 6 = 6, but is not less than 6.
.. no, x=6 is not a solution to x < 6.

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2 years ago

Simplify (4a^m+3)^3*(1/16a^1-m)^2

Marina86 [1]

The simplified answer is 27m^2

3 0

2 years ago

More help is appreciated:))

Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P $^{1}$ = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q $^{1}$ = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R $^{1}$ = (10, 11)

Therefore, P $^{1}$ = (8, 5), Q $^{1}$ = (3, 14), R $^{1}$ = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0

2 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

1 year ago