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Zarrin [17]
3 years ago
10

Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3?

Mathematics
2 answers:
Sedbober [7]3 years ago
3 0

Answer:

(1,1)

Step-by-step explanation:

The choices are not visible, however are unnecessary to solve this problem.

Given y = 3x - 2 and y = -2x + 3

[Set them equal to each other]

3x - 2 = -2x + 3

[Find x]

3x + 2x - 2 = 3

3x + 2x = 5

5x = 5

x = 1

[Plug x = 1 to both equations to check and find y]

y = 3x - 2

y = 3(1) - 2 = 3 - 2 = 1

y = -2x + 3

y = -2(1) + 3 = -2 + 3 = 1

Both are equal to y = 1 when x = 1

The point is then: (1,1)

vfiekz [6]3 years ago
3 0

Answer:

(1, 1).

Step-by-step explanation:

y = 3x − 2

y = -2x + 3

Subtracting:

0 = 5x - 5

5x = 5

x = 1.

Put x = 1 into the first equation:

y = 3(1) - 2 = 1.

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A,B,C,D are points on the circumference of a circle centre o
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The points A,B,C,D make up the circumference of the circle

The measure of angle BAD is 65 degrees

<h3>How to determine the measure of angle BAD?</h3>

The measure of angle ODB is given as:

ODB = 25 degrees

Considering the triangle BOD, we have:

ODB + BOD + DBO = 180

Where:

ODB = DBO = 25

So, we have:

25 + BOD + 25 = 180

Solve for BOD

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The angle at an arc is twice the angle at the circumference.

So, we have:

BOD = 2 * BAD

Substitute 130 for BOD

130 = 2 * BAD

Divide both sides by 2

65 = BAD

Hence, the measure of angle BAD is 65 degrees

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7 0
2 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

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b^2 - 4ac = 7

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Substitute values for a and b in b^2 - 4ac = 7

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Evaluate

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Subtract 25 from both sides

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Divide by - 6

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So, we have:

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b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

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