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IRISSAK [1]
3 years ago
8

Define the variables for the situation. Then enter an equation.

Mathematics
1 answer:
svp [43]3 years ago
8 0

Answer:

<u>Definitions of the variables in the situation:</u>

J = Jana's age

S = Sister's age

<u>The Equation:</u>

J + 8 = S

Step-by-step explanation:

<u>Explanation: </u>

In the equation we will use the variable J for Jana and S for Janna's sister. Since we know Jana's age plus 8 equals her sister's age, the equation will be J + 8 = S

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p-4

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It is like asking to write an expression for the difference of 7 and 4: 7 - 4.

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What is y=4x-1 in standard form?
defon

Answer:

<em>Algebra Examples</em>

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Consider the sequence following a minus 8 pattern: 9, 1, −7, −15, ….
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Step-by-step explanation:

The given pattern: 9, 1, -7, -15, ….

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a_n=a+(n-1)d

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4 years ago
The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

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Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

6 0
2 years ago
The volume of a barrel of oil is calculated as 257,166 cm³.
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