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3 years ago

Please help . Put step by step workings please. Also I need help with both questions

Mathematics

1 answer:

Slav-nsk [51]3 years ago

8 0

1. Vertex is (-3,-7), y intercept: (0,10) 2. Vertex is (-3,13) and y int is (0, -15)

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an isosceles triangle has a vertex angle of 21.21 degrees. two sides of the triangle are each 17.91 ft long. whats the area of t

lubasha [3.4K]

Answer:

The area of triangle is $A=58.02\ ft^{2}$

Step-by-step explanation:

Let

B -----> the measure of the vertex angle of the isosceles triangle ABC

a and c -----> the two congruent sides of the isosceles triangle ABC

we know that

The area of a triangle applying the law of sines is equal to

$A=\frac{1}{2}(a)(c)sin(B)$

we have

$a=c=17.91\ ft$

$B=21.21\°$

substitute in the formula

$A=\frac{1}{2}(17.91)(17.91)sin(21.21\°)$

$A=58.02\ ft^{2}$

7 0

3 years ago

16^1/4 = a. 1/2 b. 2 c. 4

stiv31 [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

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Am i true S six C cruel H hours O of O our L Life

Licemer1 [7]

Answer:

yes school is amazing

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2 years ago

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Please help solve this question

Rasek [7]

95141 1404 393

Answer:

arc BC: 8.55 cm
chord BC: 8.03 cm

Step-by-step explanation:

The length of an arc that subtends central angle α will be ...

s = rα . . . . where α is in radians

The central angle BOC is twice the measure of angle QBC, so is 70°, or 7π/18 radians. So, the length of arc BC is ...

s = (7 cm)(7π/18) ≈ 8.55 cm . . . arc BC

For central angle α and radius r, the chord subtending the arc is ...

c = 2r·sin(α/2)

c = 2(7 cm)sin(35°) ≈ 8.03 cm . . . . chord AB

5 0

3 years ago

How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2

Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

$\log_{2}[\log_{2}(\sqrt{4x})]=1$

i.e. $\log_{2}(\sqrt{4x})=2^{1}$

i.e. $\sqrt{4x}=2^{2}$

i.e. $\sqrt{4x}=4$

i.e. $4x=4^{2}$

i.e. $4x=16$

i.e. $x=4$

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is $( 0,\infty )$ .

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0

3 years ago

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