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34kurt
3 years ago
8

Please help . Put step by step workings please. Also I need help with both questions

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
1. Vertex is (-3,-7), y intercept: (0,10) 2. Vertex is (-3,13) and y int is (0, -15)
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an isosceles triangle has a vertex angle of 21.21 degrees. two sides of the triangle are each 17.91 ft long. whats the area of t
lubasha [3.4K]

Answer:

The area of triangle is A=58.02\ ft^{2}

Step-by-step explanation:

Let

B -----> the measure of the vertex angle of the isosceles triangle ABC

a and c -----> the two congruent sides of the isosceles triangle ABC

we know that

The area of a triangle applying the law of sines is equal to

A=\frac{1}{2}(a)(c)sin(B)

we have

a=c=17.91\ ft

B=21.21\°

substitute in the formula

A=\frac{1}{2}(17.91)(17.91)sin(21.21\°)

A=58.02\ ft^{2}

7 0
3 years ago
16^1/4 = <br> a. 1/2<br> b. 2<br> c. 4
stiv31 [10]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
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Am i true<br> S six<br> C cruel<br> H hours<br> O of<br> O our<br> L Life
Licemer1 [7]

Answer:

yes school is amazing

4 0
2 years ago
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Please help solve this question​
Rasek [7]

95141 1404 393

Answer:

  • arc BC: 8.55 cm
  • chord BC: 8.03 cm

Step-by-step explanation:

The length of an arc that subtends central angle α will be ...

  s = rα . . . . where α is in radians

The central angle BOC is twice the measure of angle QBC, so is 70°, or 7π/18 radians. So, the length of arc BC is ...

  s = (7 cm)(7π/18) ≈ 8.55 cm . . . arc BC

__

For central angle α and radius r, the chord subtending the arc is ...

  c = 2r·sin(α/2)

  c = 2(7 cm)sin(35°) ≈ 8.03 cm . . . . chord AB

5 0
3 years ago
How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2
Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

\log_{2}[\log_{2}(\sqrt{4x})]=1

i.e. \log_{2}(\sqrt{4x})=2^{1}

i.e. \sqrt{4x}=2^{2}

i.e. \sqrt{4x}=4

i.e. 4x=4^{2}

i.e. 4x=16

i.e. x=4

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is ( 0,\infty ).

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does  not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0
3 years ago
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