Answer:
The area of triangle is 
Step-by-step explanation:
Let
B -----> the measure of the vertex angle of the isosceles triangle ABC
a and c -----> the two congruent sides of the isosceles triangle ABC
we know that
The area of a triangle applying the law of sines is equal to

we have


substitute in the formula


Answer:
c
Step-by-step explanation:
95141 1404 393
Answer:
- arc BC: 8.55 cm
- chord BC: 8.03 cm
Step-by-step explanation:
The length of an arc that subtends central angle α will be ...
s = rα . . . . where α is in radians
The central angle BOC is twice the measure of angle QBC, so is 70°, or 7π/18 radians. So, the length of arc BC is ...
s = (7 cm)(7π/18) ≈ 8.55 cm . . . arc BC
__
For central angle α and radius r, the chord subtending the arc is ...
c = 2r·sin(α/2)
c = 2(7 cm)sin(35°) ≈ 8.03 cm . . . . chord AB
Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
![\log_{2}[\log_{2}(\sqrt{4x})]=1](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%5B%5Clog_%7B2%7D%28%5Csqrt%7B4x%7D%29%5D%3D1)
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.