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3 years ago

Please help . Put step by step workings please. Also I need help with both questions

Mathematics

1 answer:

Slav-nsk [51]3 years ago

8 0

1. Vertex is (-3,-7), y intercept: (0,10) 2. Vertex is (-3,13) and y int is (0, -15)

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3y²z(2y²z + 4yz - y + z) = <br> 6y⁴z² + 12y³z² - 3y³z + 3y²z

lord [1]

18y⁸z²=18y⁸z², you have to simplify it and add like terms to get your answer

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3 years ago

Solve for variable its in pre algebra

Natalka [10]

Answer:

Step-by-step explanation:

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2 years ago

Please need it in 5 mins

Vilka [71]

Answer:

70,110,110,110

Step-by-step explanation:

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3 years ago

PLEASE HELP!!! 15 PTS!!

kherson [118]

Answer:

$\large\boxed{C.\ (2,\ -45^o)}$

Step-by-step explanation:

Regular coordinates (x, y)

Polar coordinates (r, φ)

$r=\sqrt{x^2+y^2}\\\\\psi=\arctan\frac{y}{x}$

We have the point

$(\sqrt2,\ -\sqrt2)$

Substitute:

$r=\sqrt{(\sqrt2)^2+(-\sqrt2)^2}=\sqrt{2+2}=\sqrt4=2\\\\\psi=\arctan\left(\frac{-\sqrt2}{\sqrt2}\right)=\arctan(-1)=-45^o$

6 0

3 years ago

Eva payrolls for on a number cube and the number of cubes roll 24 times then what is a reasonable prediction for the number of s

Allushta [10]

Answer:

The reasonable prediction for successful rolls is 4.

Step-by-step explanation:

Assuming the rolling cube is a fair 6 sided cube, so the probability of success of one roll is given as

$P(Success)=\dfrac{Number\ of\ successful\ events}{Number\ of\ total\ events}$

$P(Success)=\dfrac{1}{6}$

The total success is given as

$P(Total\ Success)=P(Success)\times Number\ of\ events$

For 24 rolls it is given as

$P(Total\ Success)=P(Success)\times Number\ of\ events\\P(Total\ Success)=\dfrac{1}{6}\times 24\\P(Total\ Success)=4$

So the reasonable prediction for successful rolls is 4.

3 0

3 years ago