Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
First find a common denominator so you can compare them easier. I chose 12. Multiply the numerator and denominator by the number that makes the denominator 12. 2/3 is multiplied by 4 and 2/4 is multiplied by 3. You are left with 8/12 and 6/12. 8/12 is bigger so it looks like
8/12>6/12
Hope this helps!
The answer to the question is 13
Answer is d
Step-by-step explanation:
If you multiply a^6 and a it equals a^7