Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
Learn more about Boyce-Codd Normal Form at
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<span>1x + 2x = 15
3x = 15
3x/3 = 15/3
x = 5
Gemma = 1x, Zak = 2x therefore Gemma = 5 and Zak = 10</span>
Answer:
Rowan ate 
of the pizza
Step-by-step explanation:
Nap ate 2/5 of the pizza Rowan ate 2/3 of the pizza that was left how much of the pizza did Rowan eat?
Nap: can be rewritten as 
Rowan: 
can be rewritten as 
After Nap ate 2/5 of the pizza, there is 3/5 pizza left.
can be rewritten as 
=
Rowan ate of the pizza
Hope this helps!
First, let's simplify the equation.
- Apply the Distributive Property to the right hand side of the equation
- Subtract
from both sides of the equation
Since the right and left sides of the equation are equal, we know that there must be an infinite number of solutions. This means that there is an infinite amount of values that we can substitute for 
for the equation to be true.
