Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations.
8a + 4s = 880
a - s = 20
We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:
8a + 4s = 880
4a - 4s = 20
Notice the s-variables will cancel:
12a = 900
a = 75
Now we plug in the amount of adult tickets to solve for the student ones.
75 - s = 20
- s = - 55
Divide both sides by - 1
s = 55.
There were 55 student tickets sold and 75 adult tickets.
Answer:
1: 42
2: 42
Step-by-step explanation:
1: Subtract and plus the first equation using a calculator
2: Now subtract and plus the second equation using a calculator
<em><u>Answers:</u></em>
<em><u></u></em>
1: 42
2: 42
<em><u>Hope this helps.</u></em>
Answer:
I would need to be able to see the expressions available.
Step-by-step explanation:
Answer:2.8
Step-by-step explanation: 42/15
1. simplify 11/5
- 58/10 - 11/5 =0
2. Divide z by 11/5
- 58/10 - 5z/11 =0
3. simplify 29/5
29/5 - 5z/11 =0
4. calculating the least common multiple
4.1 find the least common multiple
the left denominator is: 5
the right deniminator is: 11
least common multiple:55
....
solution z=319/25 = 12.760
