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3 years ago

Solve the inequality -5x > 35

Mathematics

2 answers:

galina1969 [7]3 years ago

5 0

-5x > 35
-x > 7
(Divide it by 5)

Licemer1 [7]3 years ago

5 0

Answer:

x is greater than or equal to -8

Step-by-step explanation:

35/-5 is 7 and since the sign is greater than that means that -5x will be greater than 35

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A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a pers

Arturiano [62]

Answer:

A person who watches 8.5 hours of TV can do 30.4 sit ups.

Step-by-step explanation:

The regression equation is used to predict or estimate the value of the response (or dependent) variables using the information about the explanatory (or predictor) variables.

The general form of a regression equation is:

$y=ax+b$

Here,

y = dependent variable

x = independent variable

a = intercept

b = slope

The regression equation representing the relationship between hours of TV watched per day (x) and number of sit ups a person can do (y) is:

$y=-0.74x+36.359$

Compute the number of sit ups a person who watches 8.5 hours of TV can do as follows:

$y=-0.74x+36.359$

$=(-0.74\times 8.5)+36.359\\=-6.29+36.659\\=30.369\\\approx 30.4$

Thus, a person who watches 8.5 hours of TV can do 30.4 sit ups.

6 0

3 years ago

Use the distributive property to rewrite and find 4*(25+4)

jek_recluse [69]

100+16=116 is the right answer

4 0

2 years ago

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

7 0

2 years ago

No spams :))))))))))))

Alexandra [31]

A. Youre getting anyone willing to answer the survey, most of them might be in a rush so maybe they’ll decline so i think A is the safesy

3 0

1 year ago

Read 2 more answers

Given function f(x)=x^2+5, determine the value of f(f(5))

zalisa [80]

Answer:

905

Step-by-step explanation:

So your original equation is f(x) = x² + 5

First lets work with the stuff inside the parentheses.

f(5) = 5² + 5 = 30

So now you are finding,

f(f(5)) => f(30)

f(30) = 30² + 5 = 900 + 5 = 905

8 0

3 years ago