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musickatia [10]
3 years ago
10

Find the mean. 20, 5, 45, 90, 60, 45, 30, 10, 20, 45, 15,25

Mathematics
2 answers:
maksim [4K]3 years ago
7 0

Answer:

34.166

Step-by-step explanation:

Mean=(Sum of all the numbers)/12=410/12=34.166

aliina [53]3 years ago
6 0

\huge\textsf{Hey there!}

\bullet \large\textsf{ Finding the mean you have to add up all of your numbers \& divide it}\\\large\textsf{by the total numbers in your data plot}

\mathsf{\dfrac{20 + 5 + 45 +  90 + 60 + 45 + 30 + 10 + 20+ 45 + 15 + 25}{12}}

\mathsf{20 + 5 + 45 +  90 + 60 + 45 + 30 + 10 + 20+ 45 + 15 + 25}

\mathsf{= 25 + 45 + 90 + 60 + 45 + 30 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 70 + 90 + 60 + 45 + 30 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 160 + 60 + 45 + 30 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 220 + 45 + 30 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 265 + 30 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 295 + 10 + 20 + 45 + 15 + 25}

\mathsf{= 305 + 20 + 45 + 15 + 25}

\mathsf{= 325 + 45 + 15 + 25}

\mathsf{= 370 + 15 + 25}

\mathsf{= 385 + 25}

\mathsf{= \bf 410}

\mathsf{= \dfrac{410}{12}}

\mathsf{\dfrac{410}{12} \approx \bf 34.1667}

\boxed{\boxed{\huge\textsf{Thus, your ANSWER is: \boxed{\mathsf{ \bf \underline{{\star 34.1667\star}}}}}}}}\huge\checkmark

\huge\textsf{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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In a young woman's study group, 7 percent of the students are from the town where the young woman's school is located, 80 percen
Umnica [9.8K]

Answer: the percent of study group students from outside the state is 13%

Step-by-step explanation:

The total number of students in the young woman's study group that are from the town where the young woman's school is located is 7%

The total number of students in the young woman's study group that are from in-state (but not from the school's town) is 80%.

Since the rest are from outside the state, the percent of study group students from outside the state would be

100 - (80 + 7) = 100 - 87 = 13%

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3 years ago
30 points!!!
lara31 [8.8K]

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SAS postulate

Step-by-step explanation:

AD (common)

AC = BD (both are diameters)

Angle COD = Ange AOD (vertically opposite angles)

Angle CAD = Angle BAD (angle on the circumference is half the angle at the centre)

Therefore, ABD and DCA are congruent by SAS postulate

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Write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral A. B. C. D IN THE PICTURE
Mice21 [21]

Answer:

The sequence of transformation is reflected across the y-axis and translated 2 units down

Step-by-step explanation:

Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) translate h units to the right

∴ Its image is (x + h , y)

- If point (x , y) translate h units to the left

∴ Its image is (x - h , y)

- If point (x , y) translate k units up

∴ Its image is (x , y + k)

- If point (x , y) translate k units down

∴ Its image is (x , y - k)

* Now lets solve the problem

∵ The vertices of figure ABCD are:

  A (-1 , 3) , B (1 , 0) , C (2 , 3) , D (1 , 4)

∵ The vertices of figure A"B"C"D" are:

  A" (1 , 1) , B" (-1 , -2) , C" (-2 , 1) , D" (-1 , 2)

* Lets compare between ABCD and A"B"C"D"

∵ All x-coordinates has opposite signs

  -1 ⇒ 1 , 1 ⇒ -1 , 2 ⇒ -2 , 1 ⇒ -1

∴ The ABCD is reflected across the y-axis

∵ All y-coordinates subtracted by 2

 3 ⇒ 1 , 0 ⇒ -2 , 3 ⇒ 1 , 4 ⇒ 2

∴ The ABCD is translated 2 units down

* The sequence of transformation is reflected across the y-axis

  and translated 2 units down

5 0
3 years ago
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