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Fofino [41]
3 years ago
13

37 is nearest to what multiple of 10?

Mathematics
2 answers:
Kaylis [27]3 years ago
5 0
4 because 4 x 10 = 40 and 3 x 10 = 30 so 4 is closer
mr_godi [17]3 years ago
4 0
You're answer would be 40. When you round 37 it will be closer to 40 than 30.
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What is 5/6 times 120 =
Dominik [7]
Answer: you can use take out the 5 and multiply 5 by 120=600.then take out the 6 and multiply 6 by 120=720.then take 600 and 720,put it into a fraction.
6 0
3 years ago
How much will the guitar be worth in 10 years?
Contact [7]

Answer:

$44487

Step-by-step explanation:

If you plug in 10 for t, you are left with the following equation:

V=12000(1.14)^{10}=12000\cdot 3.7072\approx 44487. Hope this helps!

8 0
2 years ago
Read 2 more answers
Hlp!
zzz [600]

Answer:

Option B

x ≥ (-5)

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • -3(x + 4) ≥ x + 8

So,

-3(x + 4) ≥ x + 8

-3x – 12 ≥ x + 8

Add both sides 12 we get,

-3x – 12 + 12 ≥ x + 8 + 12

-3x ≥ x + 20

Similarly, subtract x from both sides we get,

-3x – x ≥ x – x + 20

-4x ≥ 20

Then, divide both sides by (-4) we get,

-4x/(-4) ≥ 20/(-4)

x ≥ -5

Thus, The answer is x ≥ (-5).

7 0
2 years ago
Please urgent answer needed
Daniel [21]

Answer:

8

Step-by-step explanation:

5 0
3 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
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