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kow [346]
3 years ago
13

Simplify 4(12 + 6) using distributive property

Mathematics
2 answers:
Doss [256]3 years ago
7 0

Answer:

72

Step-by-step explanation:

Tomtit [17]3 years ago
3 0

Answer:

Step-by-step explanation:

4(12+6)

4 times 12 is 48

4 times 6 is 24

48+24

add them both together

72

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Comparison Keshawn goes to the store to buy milk for his baby sister. He sees the
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he should buy 128 oz of milk for 6.49

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4.99 divided by 64 is 7 cents too 8 if rounding

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Let x represents the amount of a transaction and let f(x) represents the amount Isabel is charged for the transaction write a fu
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Answer:

f(x) = \frac{Px}{100}

Step-by-step explanation:

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So, if the transaction amount is x, then the charge for that transaction will be

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Therefore, if f(x) represents the amount Isabel is charged for the transaction then we can write f(x) = \frac{ Px }{ 100 }, where P% is the rate of charge. ( Answer )

4 0
3 years ago
What is 11.5+y in word phase
Ksivusya [100]
Eleven and five tenths plus another number
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%284v%5E%7B-3%7D%20%29%5E3%2F3v%5E%7B-8%7D" id="TexFormula1" title="(4v^{-3} )^3/3v^{-8}" alt=
Svet_ta [14]

Answer:

=\frac{64}{3v}

Step-by-step explanation:

One is given the following equation:

\frac{(4v^-^3)^3}{3v^-^8}

Simplify the numerator, remember to raise every number inside the parenthesis to the exponent outside of the parenthesis. Bear in mind, an exponent raised to another exponent is equal to the exponent times the exponent it is raised to. Then simplify by multiplying the number by itself the number of times that the exponent indicates.

\frac{(4v^-^3)^3}{3v^-^8}

=\frac{4^3(v^-^3)^3}{3v^-^8}

=\frac{4^3v^-^9}{3v^-^8}

=\frac{64v^-^9}{3v^-^8}

Bring the variable (v) in the denominator (value under the fraction bar) to the numerator (value ontop of the fraction bar) by multiplying its exponent by (-1). This can be done simply because all operations in this equation are multiplication or division, remember, an exponent is another form of multiplication.

=\frac{64v^-^9}{3v^-^8}

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

Simplify, remember, multiplying two numbers with the same base that have an exponent is the same as adding the two exponents,

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

=\frac{(64v^-^9)(v^8)}{3}

=\frac{64v^-^9^+^8)}{3}

=\frac{64v^-^1}{3}

Now bring the variable to the denominator so that there are no negative exponents. Use a similar technique that was used to bring variables with exponents to the numerator.

=\frac{64v^-^1}{3}

=\frac{64}{3(v^(^-^1^)^(^-^1^))}

=\frac{64}{3v^1}

=\frac{64}{3v}

5 0
3 years ago
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