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anyanavicka [17]
3 years ago
14

How does the numbers of zeros in the product of 8 and 5000 compare to the number of zeros in the factors?

Mathematics
1 answer:
o-na [289]3 years ago
6 0
If product means to multiply than
5000*8= 40000
Answer: There is one more zero in the product.
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Help i dont remember dis stuff from last year
Kaylis [27]

See below for the solution to the systems of equations

<h3>How to solve the systems of equations?</h3>

<u>System of equations 1</u>

Here, we have

3x - 4y = -16

3x + 4y = 8

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, the point of intersection of the equations is (-4/3, 3)

Hence, the solution to the system is (-4/3, 3)

<u>System of equations 2</u>

Here, we have

-x  = - 6 + 2y

-18 + 6y = -3x

We start by plotting the graph of both equations

Next, we write out the point of intersection of the equations

See attachment for the equation of the system

From the attached graph, both lines are on each other

This means that the system of equations have infinite many solutions

Read more about system of equations at:

brainly.com/question/14323743

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3 0
1 year ago
For triangle xyz , the measures of angles x,y, and Z are known. Which method should be used to start solving triangle xyz?
Kisachek [45]

Neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

<h3>Solving trianngles using the laws of sines & cosines </h3>

The law of sines is written as

\frac{sinA}{a}=\frac{sinB}{b}= \frac{sinC}{c}

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

  1. Two angles and one side, or
  2. Two sides and a non-included angle

The law of cosines is written as

a² = b² + c² -2bc cosA, or

b² = a² + c² - 2ac cosB, or

c² = a² + b² -2ab cosC

Where a,b, and c are sides of any given triangle and A,B, and C are the angles.

This law is used when we are given either

  1. Three sides or
  2. Two sides and the included angle

Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.

Hence, neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used

Learn more on Solving triangles using the laws of sines & cosines here: brainly.com/question/22339733

5 0
2 years ago
BC =<br> Round your answer to the nearest hundredth.<br> B<br> 50°<br> 7
Brrunno [24]

Answer:

BC = 5.87

Step-by-step explanation:

Reference angle = 50°

Side Opposite to reference angle = 7

Adjacent side = BC = ?

Apply trigonometric function, TOA, thus:

Tan 50 = Opp/Adj

Tan 50 = 7/BC

BC × Tan 50 = 7

BC = 7/Tan 50

BC = 5.87369742 ≈ 5.87 (nearest hundredth)

4 0
3 years ago
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