How does the numbers of zeros in the product of 8 and 5000 compare to the number of zeros in the factors?
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See below for the solution to the systems of equations
<h3>How to solve the systems of equations?</h3><u>System of equations 1</u>
Here, we have
3x - 4y = -16
3x + 4y = 8
We start by plotting the graph of both equations
Next, we write out the point of intersection of the equations
See attachment for the equation of the system
From the attached graph, the point of intersection of the equations is (-4/3, 3)
Hence, the solution to the system is (-4/3, 3)
<u>System of equations 2</u>
Here, we have
-x = - 6 + 2y
-18 + 6y = -3x
We start by plotting the graph of both equations
Next, we write out the point of intersection of the equations
See attachment for the equation of the system
From the attached graph, both lines are on each other
This means that the system of equations have infinite many solutions
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Neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used
<h3>Solving trianngles using the laws of sines & cosines </h3>The law of sines is written as
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Two angles and one side, or
- Two sides and a non-included angle
The law of cosines is written as
a² = b² + c² -2bc cosA, or
b² = a² + c² - 2ac cosB, or
c² = a² + b² -2ab cosC
Where a,b, and c are sides of any given triangle and A,B, and C are the angles.
This law is used when we are given either
- Three sides or
- Two sides and the included angle
Now, for triangle xyz, which the measures of angles X,Y, and Z are known, neither law can be used to solve the triangle.
Hence, neither the <u>laws of sines</u> nor the <u>law of cosines</u> can be used to solve the triangle. The correct option is the third option - neither law can be used
Learn more on Solving triangles using the laws of sines & cosines here: brainly.com/question/22339733