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3 years ago

Please explain to me how to do this or give me the answer.

Mathematics

1 answer:

Jobisdone [24]3 years ago

7 0

All you have to do is take a picture of the question and crop it

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The expression 9n + 3 represents the perimeter (in meters) of the triangle. Write an expression in the simplest form that repres

AlexFokin [52]

Answer:

4n+2

Step-by-step explanation:

add all sides =9n+3
3n+2+2n-1=9n+3
add liketerms 5n+1=9n+3
put liketerms together 9n-5n+3-1
ans hence is 4n+2

5 0

3 years ago

If g(3) = 5 and g(-1) = 5, explain why g(x) does not have an inverse.

Alenkinab [10]

g(x) cannot have an inverse because it gives the same output value for two individual input values.

In this case, g(x) is 5 when x is both 3 and -1. Hence, g(x) does not have an inverse.

Let me know if you have any questions, thanks!

4 0

3 years ago

I need help solving this practice question solve for x

zloy xaker [14]

X = 6
9/12 = 0.75
6/8 = 0.75

3 0

3 years ago

HELP PLEASE!!!<br> Rewrite using the distributive property. -(6x-17)=[?]x+[]

EleoNora [17]

Answer:

-6x + 17

Step-by-step explanation:

-(6x - 17)

= -6x + 17

=》Negative × negative = positive

=》 Positive × negative = negative

Hope it helps ⚜

6 0

2 years ago

Read 2 more answers

Using Newton's Law of Cooling. You are a medical examiner called to an abandoned house in which a dead body has been discovered.

Artyom0805 [142]

A) The differential equation comes from the fact that the rate of temperature change is proportional to the difference in temperatures.
$\frac{dT}{dt} = \alpha(T -52)$

B) Find general solution by separating variables and integrating $\int\frac{dT}{T-52} = \alpha \int dt \\ ln (T-52) = \alpha t + C \\ T = C e^{\alpha t} +52$ :

C) Initial condition is t=0, T = 87
$87 = C +52 \\ C = 35$

D) Total time elapsed is 10 minutes, new temperature is 84
$84 = 35 e^{10\alpha} +52$
solve for alpha
$e^{10\alpha} =\frac{32}{35} \\ \alpha = \frac{ln(32/35)}{10} \\ \alpha = -.00896$

E) Temperature function is:
$T = 35 e^{-.00896 t} +52$
solving for t
$t = \frac{ln (\frac{T-52}{35})}{-.00896}$
Plug in T = 98.6
$t = -31.95$

This is approximately 32 minutes before he arrived or about 1:20 AM

3 0

3 years ago