I can answer most of them!
You almost had it right! remember the equation of a circle is
(x - h)^2 + (y - k)^2 = r^2. the center is (h,k) and r is the radius.
(x - 0)^2 + (y - 0)^2 = 5^2
x^2 + y^2 = 25 <<< your answer
hope that helps, God bless!
Answer:
Option 4. x = 0
Step-by-step explanation:
we know that
The rule of the reflection of a point across the y-axis is equal to
(x,y) -----> (-x,y)
The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same
The coordinates of triangle PQR are
P(1, 4), Q(3, 6), and R(5, 2)
Applying the rule of the reflection across the y-axis we have
P(1, 4) -----> P'(-1, 4)
Q(3, 6) ----> Q'(-3, 6)
R(5, 2)----> R'(-5, 2)
The reflection line is the y-axis
Remember that the equation of the y-axis is x=0
therefore
The equation of the reflection line is x=0
Answer:
64k^2 - 16k +1
Step-by-step explanation:
We can rewrite this as
(-8k+1) ^2
We know that (a+b)^2 = a^2 +2ab +b^2
Let a = -8k and b = 1
(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2
=64k^2 - 16k +1
I think its B. False if im wrong sorry hope this helped tho :p
