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2 years ago

If you toss a coin and spin the spinner, what is the probability of landing on heads and spinning blue?

Mathematics

1 answer:

ivann1987 [24]2 years ago

4 0

Answer:

Step-by-step explanation:

There are two sides on a coin, heads and tails. So, the probability of flipping heads is going to be 1/2, as there is one chance out of the two options that you will flip a head. As for spinning blue, there are 3 options that are blue out of the four color options given. So, the probability of spinning blue would be 3/4. Hope this helped :) Take this with a grain of salt, though. It's been a while since I reviewed probabilities.

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18=30-r30 solve for r

trasher [3.6K]

Answer:

r =

Step-by-step explanation:

r=30√12,−30√12

3 0

2 years ago

Read 2 more answers

34% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 student are sampled, so $n = 10$

34% of college students say they use credit cards because of the rewards program, so $\pi = 0.34$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157$

$P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162$

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573$

$P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320$

$P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82$

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0

2 years ago

What is the Volume of the shape below?

Leona [35]

Answer:

v=720m^3

Step-by-step explanation:

v=lwh

volume=length x width x height

v=15 x 8 x 6

v=720m^3

hope this helps :)

5 0

2 years ago

Read 2 more answers

PLEASE HELP!! How many solutions can be found for the equation −4x − 11 = 2(x − 3x) + 13?

PilotLPTM [1.2K]

Answer: $No~Solution$ $s$

Step-by-step explanation:

Let's factor then solve to find the complex solutions.

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : $-4x-11=2(x-3x)+13$

Equations that are never true:

$1.1 ~~~~ Solve : -24 = 0$

This equation has no solution.

A non-zero constant never equals zero.

Therefore your answer is $No~Solution$

3 0

1 year ago

What is 12 divided by 3 as an algebraic expression

butalik [34]

12/3 or the same thing as ur question but just add a division sign, eg. difference of two and one that would be 2-1

6 0

2 years ago