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Gemiola [76]
3 years ago
12

If you toss a coin and spin the spinner, what is the probability of landing on heads and spinning blue?

Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

Step-by-step explanation:

There are two sides on a coin, heads and tails. So, the probability  of flipping heads is going to be 1/2, as there is one chance out of the two options that you will flip a head. As for spinning blue, there are 3 options that are blue out of the four color options given. So, the probability of spinning blue would be 3/4. Hope this helped :) Take this with a grain of salt, though. It's been a while since I reviewed probabilities.

You might be interested in
How many more students arrive by school bus than by car?
sp2606 [1]

Answer:

125 more students arrive buy school bus than by car

Step-by-step explanation:

20% + 25% + 15% = 60%

Bus

100 - 60 = 40% ( bus = 40%)

40% = 0.4

0.4 × 500 = 200 (200 students get to school by the school bus)

Car

15% = 0.15

0.15 × 500 =

car = 75 (75 students get to school by car)

difference

200 - 75 = 125 students (125 more students get to school on the school bus then by a car)

8 0
3 years ago
Rob saves £500 in his bank account.
dmitriy555 [2]

Answer:

step 1: =4% of £500

=20

=20 × 5 years

= 100

= £500 + £100

=£600 ....therefore Rob will have £600 in his bank account after years.

4 0
3 years ago
Uppose a triangle has a,b and c what must be true?
alexdok [17]
Obtuse: b^2 + c^2 > a^2

Right: b^2 + c^2 = a^2

Acute: b^2 + c^2 < a^2



A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2


So, your Answer would be (B)
Hope this helps!!.!

6 0
3 years ago
Read 2 more answers
What is an example of a solution of zero ?
mart [117]
4-4=0 is an example of that
5 0
3 years ago
Using the given information, give the vertex form equation of each parabola.
Amanda [17]

Answer:

The equation of parabola is given by : (x-4) = \frac{-1}{3}(y+3)^{2}

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:(\frac{47}{12},-3)

The general equation of parabola is given by.

(x-h)^{2} = 4p(y-k), When x-componet of focus and Vertex is same  

(x-h) = 4p(y-k)^{2}, When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

For value of p:

p=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

p=\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}

p=\sqrt{(\frac{1}{12})^{2}}

p=\frac{1}{12} and p=\frac{-1}{12}

Since, Focus is left side of the vertex,

p=\frac{-1}{12} is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p=\frac{-1}{12}

(x-h) = 4p(y-k)^{2}

(x-4) = 4(\frac{-1}{12})(y+3)^{2}

(x-4) = \frac{-1}{3}(y+3)^{2}

8 0
3 years ago
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