Hey there!
First, we see that it's already written in slope intercept, y = mx + b where m is the slope and b is the y intercept, we just need to simplify the like terms on the right. We have:
y = 12x-5x-2
y = 7x - 2
Now that we have it in slope intercept form, whenever we have an x intercept, since it is crossing the x axis, there's no y value. We plug in 0 for y:
0 = 7x - 2
2 = 7x
2/7 = x
The x intercept is (2/7, 0)
Hope this helps!
Answer:
#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19
Step-by-step explanation:
You can solve using the quadratic equation or by solving with the perfect square
= 
x is approximately 0.37, -5.37
Answer:
Mean = 1.9
Standard deviation = 0.6
Step-by-step explanation:
The Mean is calculate by the formula:

⇒ 
Thus Mean to the nearest tenth is 1.9
Standard Deviation is the square root of sum of square of the distance of observation from the mean.
where,
is mean of the distribution.
Putting all values in the formula, We get
Standard Deviation = 0.597 ≈ 0.6
A square and a parallelogram both have 2 sets of parallel lines. A square has equal lengths for all four sides while a parallelogram doesn't. A parallelogram is a more broad idea because a parallelogram involves trapezoids, rectangles, and squares too.But a square is more specific.
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)