Percent means per one hundred so we can say that:
p/100≈(28)/(28+81+45+63+35) guessing with my old eyes :)
p/100≈28/252
p≈2800/252
p≈11.11%
So rounded to the nearest 5% you'd have:
p≈10%
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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Answer:
439cor.to 3 Sig. fig.
Step-by-step explanation:
(5+12)×6×14-(5÷2)²π×14
In order to do this, you will have to draw a triangle, then use sin, cos, and tan to solve for the distance.
I believe the correct answer would be Segment GD is parallel to segment HC. Hope this helped!
-TTL