2 years ago

If the perimeter of the rectangle is 52 inches, find the value of x -

Mathematics

1 answer:

irinina [24]2 years ago

4 0

Answer:

25/4

Step-by-step explanation:

perimeter is total length of all side

height =2(x+2) (×2 bcause has 2 side)

length =2(3x-1) (×2 bcause has 2 side)

2x+4+6x-2=52

8x-2=52

8x=50 (8x is 8 times x, so move to the other side become divide)

x=50/8

simplify

x= 25/4

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Step-by-step explanation:

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3 years ago

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Novay_Z [31]

Answer:

$x=\pm \sqrt{11} \\y=-4.$

Step-by-step explanation:

$\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \: 2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.$