Compare 4.5x10^6 and 2.1x10^8 explain how you can compare them

What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to

yuradex [85]

Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
11.333 m = radius

the area beneath an arc:

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h² ).

r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m

Area = 138.828 m² - 53.333 m²

Area = 85.4 m²


Hope this Helps! Have A Wonderful Day! :)

And as Always...

7 0

3 years ago

Marco needs to buy some cat food. At the nearest store, 5 bags of cat food cost $18.75. How much would Marco spend on 3 bags o

Ira Lisetskai [31]

Answer:

$11.25

Step-by-step explanation:

5 bags = $18.75

To find the amount for three bags, we need to find the price for each bag.

Divide 18.75 by 5.

18.75/5 = 3.75

So each bag is 3.75, and since we need to know the price for 3 bags, we need to multiply 3.75 by 3, which is 11.25.

7 0

3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

How many times larger then 2x10² is 2x10⁸

Brrunno [24]

Answer:

1,000,000 times larger

Step-by-step explanation:

2 x $10^{8}$ = 200,000,000

2 x $10^{2}$ = 200

200,000,000 divided by 200 is 1,000,000

It can also be solved by subtracting the exponents from 10. Then dividing the two number being put the scientific notation.

$10^{8} - 10^{2}$ = $10^{6$

2 ÷ 2 = 1

Now solve:

1 x $10^{6$ = 1,000,000

3 0

3 years ago

Twin brothers, Billy and Bobby, can mow their grandparent's lawn together in 97 minutes. Billy could mow the lawn by himself in

s2008m [1.1K]

Answer:

52 minutes i think im not sure i'm not in high school

Step-by-step explanation:

5 0

3 years ago