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3 years ago

Select THREE expressions that are equivalent to 12x + 8y.

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

Answer:

Step-by-step explanation:

4(3x+2y)

12x + 8y

6x+6x+4y+4y

12x + 8y

5x+3x+3x+x+6y+y+y

5x+6x+x+6y+2y

12x+8y

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Zielflug [23.3K]

The answer is for your homework is 3)

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4 years ago

What is the sum of the first 5 terms of geometric series with a1=10 and r=1/5

steposvetlana [31]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=10\\
n=5\\
r=\frac{1}{5}
\end{cases}$

$\bf S_5=10\left( \cfrac{1-\left( \frac{1}{5} \right)^5}{1-\frac{1}{5}} \right)\implies S_5=10\left( \cfrac{1-\frac{1}{3125}}{\frac{4}{5}} \right)
\\\\\\
S_5=10\left( \cfrac{\frac{3124}{3125}}{\frac{4}{5}} \right)\implies S_5=10\cdot \cfrac{781}{625}\implies S_5=\cfrac{1562}{125}$

7 0

4 years ago

The Line graph shows the number of marks Stacey scorer in her homeworks.

weqwewe [10]

Given:

The line graph shows the number of marks Stacey scored in her homeworks.

We need to determine the Stacey's mean score.

Mean score:

The total number of marks is given by

$(0\times 4)+(1 \times 5)+(2\times 3)+(3\times 4)+(4 \times 3)+(5 \times 1)$

Simplifying, we get;

$0+5+6+12+12+5=40$

Thus, the total number of marks is 40.

Sum of the number of marks scored is given by

$4+5+3+4+3+1=20$

Thus, the sum of the marks scored is 20.

The mean is given by

$Mean=\frac{40}{20}$

$Mean=2$

Therefore, Stacey's mean score is 2 marks.

4 0

3 years ago

5 ? I 8 I. replace each . with <, >, or = to make a true sentencee

Alexeev081 [22]

Answer:

Step-by-step explanation:

it's that because no matter what if it's a negative and it has those lines it turns it into a positive and it's the right answer.

4 0

3 years ago

See image. The graph of f(x) =

forsale [732]

Answer:

Step-by-step explanation:

The answer to this problem should be the 4th one.

All real numbers can't be right as 0 obviously wont work. However, it is important to remember that sqrt of a number cant be negative, so x must either be greater than or equal to -1 and 1

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3 years ago

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