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Mila [183]
3 years ago
15

a electronic store sells a certain digital camera for $126. this is 2/3 of the price that a photography store charges. what is t

he cost of the camera at the photography store?
Mathematics
1 answer:
never [62]3 years ago
4 0

Let us assume the cost of the camera at the photography store = $x.

We are given $126 is 2/3 of the price that a photography store charges.

Let us repharse above statement "$126 is 2/3 of the store price x".

Let us convert above statement in an equation now.

126 = 2/3 of x.

126 = 2/3 x.

Dividing both sides by 2/3, we get

126 ÷ 2/3 =2/3 x ÷ 2/3.

126 × 3/2 = x

378/2 =x.

x= 189.

Therefore, the cost of the camera at the photography store is $189.


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ollegr [7]

Given:

Rule of transformation is rule R x-axis ∘ T⟨–5, 3⟩.

The point is (-3,-2).

To find:

The image of given point after the transformation.

Solution:

Consider the given point be P(-3,-2).

Rule of transformation is rule R x-axis ∘ T⟨–5, 3⟩. If means first we have apply translation T⟨–5, 3⟩ after that we have to apply reflection R x-axis.

If a figure translated by T⟨–5, 3⟩, then

(x,y)\to (x-5,y+3)

P(-3,-2)\to P'(-3-5,-2+3)

P(-3,-2)\to P'(-8,1)

If a figure reflected by R x-axis, then

(x,y)\to (x,-y)

P'(-8,1)\to P''(-8,-1)

Therefore, the image of given point after transformation is (-8,-1).

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In a simple regression analysis (where y is a dependent and x an independent variable), if the y-intercept is positive, then it
Rom4ik [11]

Answer:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

\bar x= \frac{\sum x_i}{n}  

\bar y= \frac{\sum y_i}{n}  

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On this case the correct answer would be:

E.  none of the above

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Step-by-step explanation:

Assuming the following options:

A.  there is a positive correlation between X and Y

B.  there is a negative correlation between X and Y

C.  if X is increased, Y must also increase

D.  if Y is increased, X must also increase

E.  none of the above

If we want a model y = mx +b where m represent the lope and b the intercept

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

\bar x= \frac{\sum x_i}{n}  

\bar y= \frac{\sum y_i}{n}  

And we can find the intercept using this:  

b=\bar y -m \bar x  

On this case the correct answer would be:

E.  none of the above

Since the intercept has no association between the increase/decrease of the dependent variable respect to the independent variable

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yanalaym [24]
He would need to work 

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