2 years ago

Help me plssss Find m < ABC.

Mathematics

2 answers:

jonny [76]2 years ago

8 0

Answer:

m<ABC=51°

Step-by-step explanation:

The inscribed angle is half the measure of the intercepted arc. This means that angle ABC=1/2 arc AC

Using this, let's make an equation

5x+11=(1/2)(16x-26)

5x+11=8x-13

11=3x-13

24=3x

x=8

Now go back to angle ABC and substitute for x

5(8)+11=51

m<ABC=51°

SVETLANKA909090 [29]2 years ago

6 0

Answer:

m<ABC = 51

Step-by-step explanation:

m<ABC = 1/2 arc AC

(5x + 11) = 1/2(16x-26)

x=8

Plug it in

5(8) + 11 = 51

You might be interested in

Question<br><br> Find the sum.<br><br> 1/3(9−6m)+1/4(12m−8)

Umnica [9.8K]

The sum of this is =1+m

3 0

2 years ago

My math teacher just gave me a super hard question WILL GIVE CROWN!!!!

saveliy_v [14]

This one is super difficult, I see your struggle but the answer is A.

6 0

1 year ago

Read 2 more answers

Can someone please help me factor and write the equations for these two problems ?

prisoha [69]

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = $\frac{3x}{x^2-3x-10}$

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

= x(x - 5) + 2(x - 5)

= (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = $\frac{3x}{(x + 2)(x - 5)}$

Asymptotes 4

h(x) = $\frac{(x-5)}{x^{2} + 14x + 40}$

= $\frac{x-5}{x^{2}+10x+4x+40}$

= $\frac{x-5}{x(x+10)+4(x+10)}$

= $\frac{x-5}{(x+10)(x+4)}$

5 0

3 years ago

What is the value of the expression shown below? 8 + (7 + 1) 2 ÷ 4 ⋅ 2

Leni [432]

The answer is 10

8+(8)2÷4·2
8+16÷4·2 4·2=8 then 16÷8
8+2=10

just use PEMDAS

6 0

3 years ago

11. Which regular polygon has a minimum rotation of 45° to carry the polygon onto itself?

ASHA 777 [7]

Answer:

the answer is a octagon that has rotation of 45degrees

3 0

3 years ago