All categories

2 years ago

Help me plssss Find m < ABC.

Mathematics

2 answers:

jonny [76]2 years ago

8 0

Answer:

m<ABC=51°

Step-by-step explanation:

The inscribed angle is half the measure of the intercepted arc. This means that angle ABC=1/2 arc AC

Using this, let's make an equation

5x+11=(1/2)(16x-26)

5x+11=8x-13

11=3x-13

24=3x

x=8

Now go back to angle ABC and substitute for x

5(8)+11=51

m<ABC=51°

SVETLANKA909090 [29]2 years ago

6 0

Answer:

m<ABC = 51

Step-by-step explanation:

m<ABC = 1/2 arc AC

(5x + 11) = 1/2(16x-26)

x=8

Plug it in

5(8) + 11 = 51

You might be interested in

What is the equation of the graphed line in standard form?

Alona [7]

A. 12x+y=6<span>B. −2x+y=6</span>

7 0

3 years ago

Read 2 more answers

The lateral surface area of a cylinder is given by the formula S= 2πrh. Solve the equation for r.

alukav5142 [94]

Answer:

Well, with the info I have been given I would say; The L.A of a cylinder is SA+=2(pi)(r)(h).

Step-by-step explanation:

SA=Surface Area

LA=Lateral Area

Pi=3.14

R=Radius

H=Height

V=Volume

LA=2*pi*r*h <-- finds the Lateral Area of a cylinder

SA=LA+2*base or SA=2*pi*r*h+2*pi*r^2<-- finds the Surface Area of a cylinder

V=pi*r^2*h<---- Finds volume of the cylinder

8 0

3 years ago

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$