Hi, can someone please help with these two problems? thank you so much! i'll give brainliest :)

7 Find the slope of the line that passes

Free_Kalibri [48]

Answer:

y=1.6x+7.2

Step-by-step explanation:

First you want to find m or the slope so use the formula m=y2-y1/x2-x1 and you get your slope which is 1.6.

Then you plug in your slope to the equation including another coordinate or example (3,12) plugged in to make 12=1.6(3)+b. Now you can solve for b.

Once you do that you get b=7.2

So now with m=1.6 and b=7.2, you can finally make the equation.

y=1.6x+7.2

3 0

3 years ago

In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of

Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of chocolate chips = $\frac{\sum X}{n}$ = 1238.2

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 94.3

n = sample of car drivers = 16

$\mu$ = population mean number of chips in a bag

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } }$ , $1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } }$ ]

= [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0

3 years ago

FInd the slope of these graphs plz :(

Lerok [7]

Answer:

1. Slope =1.5

2. Slpe=20

Step-by-step explanation:

The first one

150/100=1.5

Second one

1/0.2=20

7 0

2 years ago

8p+8=10+7p what is the solution set

Evgesh-ka [11]

The answer is: "p = 2" .
______________________________________________________
Explanation:
______________________________________________________
Given:
______________________________________________________
" 8p + 8 = 10 + 7p " ; Solve for "p" ;

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p − 8 ;

to get:
_________________________________________
"p = 2 " ; which is our answer.
_________________________________________

8 0

3 years ago

Read 2 more answers

Whats A Tangent Line ?

lawyer [7]

A tangent is a line that touches a circle only at one point

5 0

3 years ago