Answer:
A' would be at (0,-4)
B' would be at (-2,1)
C' would be at (-2,-3)
Step-by-step explanation:
A' would be at (0,-4)
B' would be at (-2,1)
C' would be at (-2,-3)
Answer:
Step-by-step explanation:
T(1)=1=0*x^3 0*x^2 0*x 1*1 T(x)=x-1=0*x^3 0*x^2 1*x (-1)*1 T(x^2)=2x^2-6x 6=0*x^3 2*x^2 (-6)*x 6 T(x^3)=6x^3-48*x^2 141*x-141 T(x^4)=24*x^3-204*x^2 628*x-604*1 collect the coefficient matrix and take its transpose
0 0 0 6 24
0 0 2 -48 -204
0 1 -6 141 628
1 -1 6 -141 -604
Answer:
Hey there!
Let me know if this helps :)
22. 36
23. 13/2
24. 1.1, -9.1
F^-1(x) should be the answer.
