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Tema [17]
2 years ago
12

4

Computers and Technology
2 answers:
kkurt [141]2 years ago
8 0

Answer:

href

Explanation:

trust me

madam [21]2 years ago
6 0

Answer:

its the basic link

Explanation:

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Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
Which form of media allows the audience to share in and comment on the content immediatly
Luba_88 [7]

twitter

they will allow you to share comments about any topic you want

4 0
3 years ago
A batholith is an example of a(n) _____ igneous rock (one of the two main igneous rock groups).
Naily [24]
A batholith is an intrusive igneous rock.
3 0
3 years ago
Read 2 more answers
Which search strategy is most similar to greedy search?
lesya692 [45]

Answer:

I think the answer would be A.

Explanation:

If I'm wrong plz let me know (I think I may be wrong)

8 0
3 years ago
Write a function int checkBalance(char exp[]); that can take an expression as input and check whether the parenthesis used in th
mylen [45]

Answer:

Explanation:

The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.

import java.util.ArrayList;

class Brainly {

   public static void main(String[] args) {

       char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};

       char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};

       System.out.println(checkBalance(exp));

       System.out.println(checkBalance(exp2));

   }

   public static boolean checkBalance(char exp[]) {

       ArrayList<Character> symbols = new ArrayList<>();

       for (char x: exp) {

           if ((x =='[') || (x == '{') || (x == '(')) {

               symbols.add(x);

           }

           if (x ==']') {

               if (symbols.get(symbols.size()-1) == '[') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x =='}') {

               if (symbols.get(symbols.size()-1) == '{') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x ==')') {

               if (symbols.get(symbols.size()-1) == '(') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

       }

       return true;

   }

}

3 0
3 years ago
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