Answer:
see explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
You can compress them. ZIP is the most well known protocol.
Answer:
The code to this question can be given as:
Code:
int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.
newScores = oldScores; //holds value.
for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.
{
newScores.at(i) = newScores.at(i+1); //holds value in newScores.
}
newScores.at(lastVector) = oldScores.at(0); //moving first element in last.
Explanation:
- In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
- In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
- This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
- Then we use another for loop for print newScores array elements.
Ethics:
- to ensure that privacy will not be lost.
-ensuring personal information is not lost
-information in the accountings will not be submitted or shared with anyone
-information will be saved and viewed by the business.
- The business will not falsely make the accountings.
The range of cells in column A and rows 10 through 20
