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aniked [119]
2 years ago
14

Which of these correctly rearranges the terms in this polynomial so like terms are next to each other

Mathematics
1 answer:
True [87]2 years ago
8 0

Question is not complete, so i have attached it.

Answer:

B: -2x² - 6x² - 6x + 3x + 3 + 2

Step-by-step explanation:

From the image attached, the given polynomial is;

3 - 6x - 2x² + 3x - 6x² + 2

For like terms to be next to each other, we have to rearrange it as follows;

-2x² - 6x² - 6x + 3x + 3 + 2

Like terms are x² and x, thus they are now arranged next to each other.

The only option that corresponds to our answer is option B

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Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
Read 2 more answers
I would really appreciate if someone would help me i don’t understand
alekssr [168]

Answer:

D. 48

Step-by-step explanation:

In the experiment, 16/40 landed exactly on heads. If you do 16/40 * 3/3 = 48/120.

This means that you can estimate 48 of the next 120 trials have 2 coins showing heads.

6 0
3 years ago
I need help please !!!!!!
garri49 [273]

Answer:

And the probability that the first die shows an odd number is 1/2, as is the probability that the second does. Since the dice fall independently, P(both are odd) = P(first is odd)*P(second is odd) = (1/2)*(1/2) = 1/4. Therefore P(at least one is even) = 1 - 1/4 = 3/4.

7 0
3 years ago
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Subtract: (4n + 7) - (7n - 8)
Furkat [3]
4n+7−(7n−8)

=4n+7+−1(7n−8)

=4n+7+−1(7n)+(−1)(−8)

=4n+7+−7n+8

Combine Like Terms

=4n+7+−7n+8

=(4n+−7n)+(7+8)

=−3n+15

4 0
3 years ago
Solve equation by factoring.<br><br> X3 - 49x = 0
Drupady [299]

Answer: x=7 or x=-7

x(x+7)(x-7)=0

5 0
3 years ago
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