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3 years ago

Apples cost four times as much as oranges per pound. Apples are $2.80 per pound. How much do oranges cost per pound? *

Mathematics

1 answer:

inessss [21]3 years ago

8 0

Step-by-step explanation:

Apples cost four times as much as oranges per pound.

If the cost of orange =x

then, cost of apples =4x

But,

the costs of apples =2.80$

So,4x=2.80

$\tt{ x=\dfrac{2.80}{4} }$ ⠀

$\tt{ x=0.70\$ }$ ⠀

so,oranges costs for per pound =0.70$

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jok3333 [9.3K]

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PLEASE HELP ASAP!! You used your new smart watch to record your heart rate every morning for 15 days. Select the dot plot that r

Artyom0805 [142]

The dot-plot for the data is sketched at the end of this answer.

--------------------------

The dot plot shows the <u>number of times each measure appears in the data-set.</u>

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68 appears once, thus it is 1 in the dot-plot.
69 appears three times, thus it is 3 in the dot-plot.

70 appears once, thus it is 1 in the dot-plot.
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72 appears once, thus it is 1 in the dot-plot.
73 appears five times, so it is 5 in the dot-plot.

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75 does not appears, so it is 0.
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The sketch is given at the end of this answer.

A similar problem is given at brainly.com/question/24908406

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2 years ago

An open box is to contain a volume of 3 cubic meters. Given that the material forthe sides of the box costs 6 per square meter a

bekas [8.4K]

Answer: total cost = 36/w + 36/l + 9lw

Step-by-step explanation:

The formula for determining the volume of the rectangular box is expressed as

Volume = lwh

Where lwh represents the length, width and height of the box respectively.

Since the volume of the box = 3cm³,then

lwh = 3

h = 3/lw

Since the box is open, the surface area would be

2lh + 2wh + lw

Given that the material for the sides of the box costs 6 per square meter, the total cost for the sides is

(2lh × 6) + (2wh × 6)

Substituting h = 3/lw into the above expression, it becomes.

(2l × 3/lw × 6) + (2w× 3/lw × 6)

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Since the material for the bottom costs 9per square meter, the total cost for the bottom is

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3 years ago

How do i find the unit rate?

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3 years ago

Read 2 more answers

Match the following rational expressions to their rewritten forms.

Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

$1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}$

And the rewritten forms:

$(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}$

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

$(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}$

So, correct option is 3.

$(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}$

So, correct option is 1.

$(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}$

So, correct option is 2.

$(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}$

So, correct option is 4.

The answer is also attached in the answer area.

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3 years ago