To simply determine if the solution is true. Simply plug in and or substitute the values of w for the expression. Then see if the left hand side is equal to the right side of the equation.
Solution:

1. For Best Actor
= 59 years

Z, Score for best actor named, 

Z-Score for best actor = 1.24
2. Z , Score for best supporting actor , called 
=49 years

Z-Score for best supporting actor = 0.70
Z-Score is usually , the number of standard deviations from the mean a point in the data set is.
3. As, 
So, we can say that,Option (B) The Best Actor was more than 1 standard deviation above is not unusual.
4.As, 
So, we can say that,Option(A) The Best Supporting Actor was less than 1 standard deviation below, is not unusual.
Answer:
60 Hope this helps you :)
Step-by-step explanation:
Answer:
1= 36
2= 6
3= 42
4= 162
5= 200
Step-by-step explanation: