You would use the cosine rule for this as you have 2 lines and are given the angle between them
The angle can be figured out easily as the clock has 12 equal components, meaning each component is 360/12 which is 30
As there are 5 components between A and B the angle is 30*5 =150
You can plug all of this into the cosine rule
a^2= b^2+c^2-2bcCos(A)
So a = sqrt( 10^2 +7^2 -(2*10*7) cos150)
a=16.4 to 3 sf
Answer:
it is the first one
Step-by-step explanation:
ion know how to explain it but it is
Answer:
C
Step-by-step explanation:
Volume = base * height.
The area of the base = base * height/2
That means the area of the triangular base is 8 * 5.1/2 = 20.4
The height is 9, so the volume is 20.4 * 9.
That means the volume is 183.6, which is C
Answer:
will this work or help ?
Step-by-step explanation:
The given equation governs the height versus time of the object. h(0) = 64, so the ground is considered at h = 0. The question is at what time is h = 0? So, set h = 0 and solve for t.
-16t^2 + 48t + 64 = 0
We can divide both sides of this equation by -16 for simpler numbers. We get
t^2 - 3t - 4 = 0
We can factor this equation:
(t - 4)(t + 1) = 0
So, t = 4 and t = -1 are solutions.
But, time must be positive, so t = -1 makes no sense, so we discard it. This leaves
t = 4 sec.
