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4 years ago

which movement's primary goal was the ratification of a constitutional amendment authorizing prohibition?

1 answer:

4 0

It was the primary goal of the temperance movement in the United States to get a constitutional amendment authorizing Prohibition. But prohibition was wildly unpopular.

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What’s the answer? :) A? B? C? D?

kondor19780726 [428]

Answer:

1st of all- (OFF TOPIC) you are on canvas lol

2nd- not sure, maybe B or C. Sorry if it is wrong, and I hope I could help.

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3 years ago

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PLEASE HELP ILL BRAINLIEST YOU PLEASE

monitta

17²-8²=225

√225= 15

therefore both x and y are 15 ft

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3 years ago

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Hurry! A FedEx freight truck carries three tons of packages 660 miles on 90 gallons of diesel fuel from Miami, Fl to Atlanta, Ga

artcher [175]

(a) Truck carries 90 gallons of diesel fuel to 660 miles.

So, 1 gallon of diesel fuel to 660/90 = 22/3 miles.

30 gallons of diesel fuel to $30()\frac{22}{3}$ = 220 miles.

Hence, if x-axis represents the number of miles and y-axis represents the number of gallons, then, (660, 90) and (220, 30) are points on the graph.

Join (660, 90) and (220, 30), we get the graph of a line.

Note that (0, 0) is also a point on the line.

Equation of the line is $y=\frac{22}{3} x$ .

(b) x represents the number of miles. Therefore, the possible values for x is the closed interval [0, 660].

Hence, the domain of the function is [0, 660].

7 0

3 years ago

What does 0 represent on the number line?

Ratling [72]

Answer: So zero represents the point when locating a point on the number line like negatives and positives

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3 years ago

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

3 years ago