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harina [27]
3 years ago
15

Simplify (2√27) x (3√32)

Mathematics
2 answers:
Kryger [21]3 years ago
5 0

For this case we have the following expression:

(2 \sqrt {27}) (3 \sqrt {32})

We have to:

27: 3 * 3 * 3: 3 ^ 2 * 3\\32: 16 * 2: 4 ^ 2 * 2

Rewriting the expression and simplifying we have:

(2 \sqrt {3 ^ 2 * 3}) (3 \sqrt {4 ^ 2 * 2}) =\\(2 * 3 \sqrt {3}) (3 * 4 \sqrt {2}) =\\(6 \sqrt {3}) (12 \sqrt {2}) =\\72 \sqrt {3 * 2} =\\72 \sqrt {6}

Answer:

72 \sqrt {6}

Aneli [31]3 years ago
5 0

Answer:

72√6

Step-by-step explanation:

The expression to be simplified is (2√27)×(3√32)

Before that,

\sqrt{27}=\sqrt{9\times3}= \sqrt{9}\times\sqrt{3}=3\sqrt{3}

\sqrt{32}=\sqrt{16\times2}= \sqrt{16}\times\sqrt{3}=4\sqrt{3}

This implies that (2√27)×(3√32)

=(2\times3\sqrt{3})\times(3 \times4\sqrt{2})

=6\sqrt{3}\times12\sqrt{2}

=72\sqrt{6}

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Reika [66]

{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \bf \red{ \dfrac{1}{2} +  \dfrac{1}{4} =  \dfrac{3}{4}   }

Step by step explanation :-

The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{  \bf \gray{ \dfrac{1}{2} +  \dfrac{1}{4}  =  \dfrac{1}{4} +  \dfrac{1}{2}   }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{ \bf \green{\dfrac{2 + 1}{4}  =  \dfrac{1 + 2}{4} }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{3}{4}  =  \dfrac{3}{4}} }

Answer :- The answer is 3/4

¿What is commutative property?

It is to change different ways in order of the addends the result would be the same.

Example :-

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d}  + \dfrac{a}{b}} }

I hope I've helped : )

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