Answer:
Either a or c
Step-by-step explanation:
Sorry I'm not entirely sure.
Answer:
Step-by-step explanation:
In the two independent samples application, it involves the test of hypothesis that is the difference in population means, μ1 - μ2. The null hypothesis is always that there is no difference between groups with respect to means.
Null hypothesis: ∪₁ = ∪₂. where ∪₁ represent the mean of sample 1 and ∪₂ represent the mean of sample 2.
A researcher can hypothesize that the first mean is larger than the second (H1: μ1 > μ2 ), that the first mean is smaller than the second (H1: μ1 < μ2 ), or that the means are different (H1: μ1 ≠ μ2 ). These ae the alternative hypothesis.
Thus for the z test:
if n₁ > 30 and n₂ > 30
z = X₁ - X₂ / {Sp[√(1/n₁ + 1/n₂)]}
where Sp is √{ [(n₁-1)s₁² + (n₂-1)s₂²] / (n₁+n₂-2)}
Answer:
<u>The correct answer is A. 3,120.</u>
Step-by-step explanation:
Let's solve the expression for x = -5 and y = 25, this way:
(5|x| - y³)/x
Replacing x and y, we have:
(5 * 5 - 25³)/-5 (Absolute value of -5 is 5 in the numerator but we keep it without changes in the denominator)
(25 - 15,625)/-5
-15,600/-5
3,120
<u>The correct answer is A. 3,120.</u>
Answer:
Solution given:
opposite:9
adjacent: 12

Relationship between opposite and adjacent is given by tan angle
so




#11.
hypotenuse[h]=11cm
opposite/perpendicular[P]=b cm
adjacent/base[b]=a cm
now

Relationship between height and hypotenuse is given by Sin angle
:.
Sin 62°=
doing crisscrossed multiplication
b=Sin 62°*11
:.b=9.71 cm
a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.
again
Relationship between base and hypotenuse is given by Cos angle
:.Cos 62°=
doing crisscrossed multiplication
a=Cos 62°×11
a=5.16cm
b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>