Lol, wydm???????????????????
The answer is the first one
(with blue and orange triangles)
Dilation makes things bigger
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
Answer:
Step-by-step explanation:
Given:
H(–1, –6), J(1, –3), K(–5, –1), and L(5, –5)
We know that polygons are HJKL relaxes using the scale factor 3. This means that, to find the coordinates of the vertices of the polygon H'J'K'L ', we need to multiply the coordinate system x and y coordinates of each vertex by a factor of 3 proportion as following:
- H' = (-1*3, -6*3) = (-3, -18)
- J' = (1*3 , -3*3) = (3, -9)
- K = (-5*3, -1*3) =(-15, -3)
- L = (5*3, -5*3) = (15, -15)