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ohaa [14]
3 years ago
6

Maren walks 3/5 miles in 24 minutes at a steady pace.  How long does it take her to walk 2 miles.

Mathematics
2 answers:
Ghella [55]3 years ago
7 0
It would take Maren 80 minutes, or 1 hr and 20 min. Just divide the 24 minutes by the 3 in the numerator, then find out how many 1/5's it takes to get 2 and multiply that by what you got as your quotient
Delvig [45]3 years ago
7 0
With this, you have to set up a proportion. So find the decimal of 3/5 and set that equal to 24. 
So this is what your proportion should look like: .6/24=x/2
Now you find how much she walks in one minute, so you divide .6 by 24 which is .025 of a mile. So now it will be .025 mpm. So now you multiply that by two.

She walks .05 miles in two minutes.
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F(x) = 3x + 6, find the ordered pair when x = -1.
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(-1 ; 3)

Step-by-step explanation:

when they say find the ordered pair they simply mean find the corresponding y value when x = -1

* where you see x substitute-1 *

f(-1) = 3(-1) + 6

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Which polynomial represents twice the sum of -5x^2-x+6 and 7x^2+x-1?
elena-14-01-66 [18.8K]

The polynomial that represent twice the sum of -5x^{2} - x +6 and 7x^{2} + x -1 is : 4x^{2}+10

<h3>What is a polynomial?</h3>

A polynomial is any  algebraic expression that has the least value of the power of  its variable as 2.

When the highest value of the polynomial is 2, it is a called a quadratic expression.

Analysis:

2( -5x^{2} -x +6 + 7x^{2} +x -1)

2( 2x^{2} + 5) =

4x^{2} + 10

In conclusion, the polynomial that represents the above  expressions is 4x^{2} + 10

Learn more about polynomials: brainly.com/question/2833285

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7 0
2 years ago
2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for
kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The variables are listed as follows:

  • \pi is the sample proportion, which is also the estimate of the parameter.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.90}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

n = 150, \pi = \frac{15}{150} = 0.1

The margin of error is of:

M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%

The interval is given by the estimate plus/minus the margin of error, hence:

  • The lower bound is: 10 - 2.45 = 7.55%.
  • The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}

\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}

(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

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1 year ago
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