Answer:
53/100
Step-by-step explanation:
First, we convert the fraction to a decimal number by dividing the numerator by the denominator:
8 / 15 = 0.533
There are two parts to the decimal number above:
Integer Part: 0
Fractional Part: 533
Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*
In this case, Rule I applies, so 8/15 (or 0.533) rounded to the nearest hundredth in decimal format is:
0.53
Next, we will make 8/15 rounded to the nearest hundredth in fraction format. Since you can divide our decimal format answer above by 1 and keep the same value, you can make it like this:
0.53 = 0.53/1
Then, we multiply the numerator and denominator by 100 to get rid of the decimal point:
(0.53 x 100) / (1 x 100) = 53/100
That's it. 8/15 rounded to the nearest hundredth is displayed below (simplified if necessary):
53/100
Answer:
6
Step-by-step explanation:
If each commerical is a minuets and they have six minuets than they can fit six commericals.
Answer:
Your solution is (9, 27) or x = 9, y = 27
Step-by-step explanation:
y = 2x + 9
y = 4x - 9
We can see that both of these equations equal y, so we can set them equal to each other.
2x + 9 = 4x - 9
Add 9 to both sides.
2x + 18 = 4x
Subtract 2x from both sides.
18 = 2x
Divide both sides by 2.
9 = x
Now we want to find y. To do this, plug x = 9 back into one of the original equations.
y = 2(9) + 9
Multiply.
y = 18 + 9
Add.
y = 27
Your solution is (9, 27)
Check your answer by plugging x = 9 and y = 27 back into the original equations.
y = 2x + 9
27 = 2(9) + 9
27 = 18 + 9
27 = 27
y = 4x - 9
27 = 4(9) - 9
27 = 36 - 9
27 = 27
Your answer is correct.
Hope this helps!
180-98=82 so 82 degrees is the answer
Given parameters:
Number of boxes Athena bought for the party = x
Number of cookies per box = 10
Number of cookies she brought to the party = 70
Number removed = 2 boxes
Unknown:
Equation of the number of boxes = ?
Solution:
1 box of cookies contains 10 cookies
If Athena, removed 2 boxes, in those two boxes, we have 20 cookies
Total number of cookies = 70 + 20 = 90 cookies;
So;
x = 
Therefore;
x =
boxes